Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹17800 grow to in 2 years at 20% per year compound interest (in ₹)?
- 2.Find the compound interest on ₹23100 at 12% per year for 1 year, compounded every year (in ₹).
- 3.What amount will ₹9700 grow to in 1 year at 15% per year compound interest (in ₹)?
- 4.Find the compound interest on ₹59600 at 25% per year for 1 year, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹29600 at 15% per year for 2 years (in ₹)?
- 6.A scooter is worth ₹35600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 7.Find the compound interest on ₹3200 at 15% per year for 2 years, compounded every year (in ₹).
- 8.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
- 9.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
- 10.A town has 19300 people. The population grows by 20% every year. What will the population be after 2 years?
- 11.What amount will ₹36800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 12.A town has 51200 people. The population grows by 25% every year. What will the population be after 3 years?
- 13.What amount will ₹51900 grow to in 1 year at 4% per year compound interest (in ₹)?
- 14.What amount will ₹40400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹32000 at 25% per year for 2 years (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹16000 at 5% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹7200 at 20% per year for 2 years (in ₹)?
- 18.A town has 14000 people. The population grows by 8% every year. What will the population be after 1 year?
- 19.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
- 20.Find the compound interest on ₹10400 at 12% per year for 1 year, compounded every year (in ₹).
- 21.A town has 45000 people. The population grows by 5% every year. What will the population be after 1 year?
- 22.A town has 7300 people. The population grows by 15% every year. What will the population be after 1 year?
- 23.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 24.What amount will ₹58400 grow to in 1 year at 25% per year compound interest (in ₹)?
- 25.What amount will ₹32000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 26.A scooter is worth ₹4800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
- 28.What amount will ₹43200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 29.What amount will ₹43000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 30.What amount will ₹35800 grow to in 1 year at 4% per year compound interest (in ₹)?
- 31.What amount will ₹5200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 32.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
- 34.What amount will ₹21100 grow to in 1 year at 5% per year compound interest (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹3800 at 10% per year for 2 years (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
- 37.A scooter is worth ₹22000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 38.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
- 39.A town has 21200 people. The population grows by 5% every year. What will the population be after 2 years?
- 40.What is the difference between the compound interest and the simple interest on ₹57600 at 25% per year for 2 years (in ₹)?
Answer key
- 25632
- 2772
- 11155
- 14900
- 666
- 34176
- 1032
- 46305
- 160
- 27792
- 71875
- 100000
- 53976
- 53429
- 2000
- 40
- 288
- 15120
- 64827
- 1248
- 47250
- 8395
- 23328
- 73000
- 42320
- 4560
- 352
- 84375
- 57233
- 37232
- 6877
- 37908
- 64
- 22155
- 38
- 384
- 16038
- 1986
- 23373
- 3600
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