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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 258 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹2500 at 20% per year for 3 years, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹13600 at 25% per year for 2 years (in ₹)?
  3. 3.What amount will ₹4500 grow to in 3 years at 20% per year compound interest (in ₹)?
  4. 4.Find the compound interest on ₹49300 at 20% per year for 2 years, compounded every year (in ₹).
  5. 5.A scooter is worth ₹3900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  6. 6.Find the compound interest on ₹22000 at 15% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹57500 at 4% per year for 2 years, compounded every year (in ₹).
  8. 8.A scooter is worth ₹11200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  9. 9.What amount will ₹25700 grow to in 1 year at 4% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹21600 at 15% per year for 2 years (in ₹)?
  11. 11.A scooter is worth ₹58300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  12. 12.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
  13. 13.What amount will ₹38100 grow to in 1 year at 15% per year compound interest (in ₹)?
  14. 14.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
  15. 15.A town has 13800 people. The population grows by 10% every year. What will the population be after 2 years?
  16. 16.What amount will ₹8200 grow to in 2 years at 20% per year compound interest (in ₹)?
  17. 17.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
  18. 18.What amount will ₹16800 grow to in 2 years at 15% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹33200 at 8% per year for 1 year, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹45200 at 5% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹57600 at 5% per year for 2 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹11800 at 10% per year for 2 years, compounded every year (in ₹).
  23. 23.What amount will ₹11500 grow to in 1 year at 8% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹55300 at 12% per year for 1 year, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹13300 at 4% per year for 1 year, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹31700 at 20% per year for 2 years, compounded every year (in ₹).
  27. 27.A town has 31800 people. The population grows by 12% every year. What will the population be after 1 year?
  28. 28.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
  29. 29.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹32300 at 5% per year for 1 year, compounded every year (in ₹).
  31. 31.A scooter is worth ₹2500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  32. 32.A scooter is worth ₹10400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  33. 33.What amount will ₹25100 grow to in 1 year at 4% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹50500 at 20% per year for 3 years, compounded every year (in ₹).
  35. 35.A town has 17500 people. The population grows by 8% every year. What will the population be after 2 years?
  36. 36.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹57600 at 20% per year for 1 year, compounded every year (in ₹).
  38. 38.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  39. 39.A town has 26900 people. The population grows by 15% every year. What will the population be after 1 year?
  40. 40.Find the compound interest on ₹4100 at 10% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 1820
  2. 850
  3. 7776
  4. 21692
  5. 3120
  6. 3300
  7. 4692
  8. 10108
  9. 26728
  10. 486
  11. 52470
  12. 1655
  13. 43815
  14. 27783
  15. 16698
  16. 11808
  17. 23328
  18. 22218
  19. 2656
  20. 113
  21. 5904
  22. 2478
  23. 12420
  24. 6636
  25. 532
  26. 13948
  27. 35616
  28. 64
  29. 25002
  30. 1615
  31. 1936
  32. 5850
  33. 26104
  34. 36764
  35. 20412
  36. 15250
  37. 11520
  38. 6859
  39. 30935
  40. 410

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