← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 259 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
  2. 2.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  4. 4.What amount will ₹27600 grow to in 1 year at 25% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹40100 at 10% per year for 1 year, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹13000 at 10% per year for 3 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹6400 at 25% per year for 2 years (in ₹)?
  8. 8.A scooter is worth ₹40500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  9. 9.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
  10. 10.What is the difference between the compound interest and the simple interest on ₹48400 at 10% per year for 2 years (in ₹)?
  11. 11.A town has 35100 people. The population grows by 20% every year. What will the population be after 2 years?
  12. 12.What is the difference between the compound interest and the simple interest on ₹24400 at 15% per year for 2 years (in ₹)?
  13. 13.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
  14. 14.A town has 20000 people. The population grows by 15% every year. What will the population be after 2 years?
  15. 15.What amount will ₹11600 grow to in 2 years at 25% per year compound interest (in ₹)?
  16. 16.A town has 22800 people. The population grows by 12% every year. What will the population be after 1 year?
  17. 17.What amount will ₹52000 grow to in 3 years at 10% per year compound interest (in ₹)?
  18. 18.A town has 3300 people. The population grows by 4% every year. What will the population be after 1 year?
  19. 19.What is the difference between the compound interest and the simple interest on ₹5600 at 15% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹8800 at 25% per year for 1 year, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹53700 at 25% per year for 1 year, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹7000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  24. 24.A scooter is worth ₹5200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  25. 25.A town has 50300 people. The population grows by 12% every year. What will the population be after 1 year?
  26. 26.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
  27. 27.A town has 15800 people. The population grows by 15% every year. What will the population be after 1 year?
  28. 28.What amount will ₹9000 grow to in 3 years at 20% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
  30. 30.Find the compound interest on ₹40200 at 5% per year for 1 year, compounded every year (in ₹).
  31. 31.What amount will ₹31000 grow to in 3 years at 10% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹33200 at 5% per year for 2 years (in ₹)?
  33. 33.What amount will ₹15700 grow to in 1 year at 5% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹57500 at 4% per year for 2 years, compounded every year (in ₹).
  35. 35.What amount will ₹24400 grow to in 2 years at 5% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
  37. 37.What amount will ₹40000 grow to in 2 years at 12% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹24800 at 15% per year for 2 years (in ₹)?
  39. 39.What amount will ₹26400 grow to in 1 year at 25% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?

Answer key

  1. 4575
  2. 100000
  3. 8334
  4. 34500
  5. 4010
  6. 4303
  7. 400
  8. 25920
  9. 2912
  10. 484
  11. 50544
  12. 549
  13. 416
  14. 26450
  15. 18125
  16. 25536
  17. 69212
  18. 3432
  19. 126
  20. 2200
  21. 13425
  22. 68
  23. 5103
  24. 2925
  25. 56336
  26. 1664
  27. 18170
  28. 15552
  29. 252
  30. 2010
  31. 41261
  32. 83
  33. 16485
  34. 4692
  35. 26901
  36. 304
  37. 50176
  38. 558
  39. 33000
  40. 1025

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets