Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 260 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹41200 at 25% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹52100 at 10% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
8. 8.A town has 18800 people. The population grows by 15% every year. What will the population be after 2 years?
9. 9.A scooter is worth ₹12800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
10. 10.What amount will ₹50500 grow to in 1 year at 10% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹51200 at 25% per year for 3 years, compounded every year (in ₹).
12. 12.What amount will ₹8800 grow to in 2 years at 10% per year compound interest (in ₹)?
13. 13.What amount will ₹12800 grow to in 3 years at 25% per year compound interest (in ₹)?
14. 14.What amount will ₹7000 grow to in 1 year at 5% per year compound interest (in ₹)?
15. 15.A town has 11200 people. The population grows by 25% every year. What will the population be after 3 years?
16. 16.What amount will ₹56000 grow to in 3 years at 10% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹50000 at 10% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
19. 19.A town has 13600 people. The population grows by 10% every year. What will the population be after 2 years?
20. 20.What amount will ₹29900 grow to in 1 year at 5% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹7500 at 10% per year for 2 years (in ₹)?
22. 22.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
23. 23.Find the compound interest on ₹3600 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
25. 25.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹19600 at 20% per year for 1 year, compounded every year (in ₹).
27. 27.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
28. 28.A scooter is worth ₹34100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
29. 29.What amount will ₹6000 grow to in 3 years at 20% per year compound interest (in ₹)?
30. 30.What amount will ₹35200 grow to in 2 years at 15% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹4300 at 10% per year for 1 year, compounded every year (in ₹).
32. 32.Find the compound interest on ₹50700 at 12% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹10500 grow to in 2 years at 10% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
35. 35.What amount will ₹12000 grow to in 3 years at 10% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
38. 38.A scooter is worth ₹12500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
39. 39.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹11800 at 4% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets