Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 26 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹15300 at 25% per year for 1 year, compounded every year (in ₹).
5. 5.What amount will ₹12200 grow to in 1 year at 15% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹29600 at 5% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹20500 at 20% per year for 3 years, compounded every year (in ₹).
8. 8.A town has 60000 people. The population grows by 8% every year. What will the population be after 2 years?
9. 9.What is the difference between the compound interest and the simple interest on ₹38000 at 25% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹50900 at 20% per year for 2 years (in ₹)?
11. 11.A town has 2600 people. The population grows by 4% every year. What will the population be after 1 year?
12. 12.What is the difference between the compound interest and the simple interest on ₹55900 at 20% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
14. 14.A scooter is worth ₹5000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
15. 15.What amount will ₹30400 grow to in 2 years at 15% per year compound interest (in ₹)?
16. 16.A town has 12800 people. The population grows by 5% every year. What will the population be after 1 year?
17. 17.What is the difference between the compound interest and the simple interest on ₹6200 at 10% per year for 2 years (in ₹)?
18. 18.A town has 19400 people. The population grows by 10% every year. What will the population be after 2 years?
19. 19.Find the compound interest on ₹41900 at 4% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹15700 at 20% per year for 1 year, compounded every year (in ₹).
21. 21.Find the compound interest on ₹50800 at 5% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹57500 at 4% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹5600 at 25% per year for 2 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
26. 26.A town has 12800 people. The population grows by 25% every year. What will the population be after 3 years?
27. 27.A scooter is worth ₹15200. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹27600 at 5% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
31. 31.A town has 59200 people. The population grows by 20% every year. What will the population be after 1 year?
32. 32.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹54700 at 20% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹38600 grow to in 2 years at 10% per year compound interest (in ₹)?
35. 35.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
36. 36.Find the compound interest on ₹38400 at 25% per year for 3 years, compounded every year (in ₹).
37. 37.What amount will ₹32400 grow to in 1 year at 5% per year compound interest (in ₹)?
38. 38.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹20600 at 10% per year for 2 years (in ₹)?
40. 40.A town has 18200 people. The population grows by 10% every year. What will the population be after 2 years?

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