Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 27 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
2. 2.A scooter is worth ₹2200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹28300 at 10% per year for 2 years (in ₹)?
5. 5.A town has 32000 people. The population grows by 10% every year. What will the population be after 3 years?
6. 6.A scooter is worth ₹11500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
7. 7.A town has 59900 people. The population grows by 5% every year. What will the population be after 1 year?
8. 8.A town has 10000 people. The population grows by 20% every year. What will the population be after 3 years?
9. 9.What amount will ₹10000 grow to in 2 years at 5% per year compound interest (in ₹)?
10. 10.A town has 6400 people. The population grows by 25% every year. What will the population be after 1 year?
11. 11.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹25600 at 10% per year for 2 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹2200 at 12% per year for 1 year, compounded every year (in ₹).
14. 14.What amount will ₹1600 grow to in 3 years at 25% per year compound interest (in ₹)?
15. 15.A scooter is worth ₹11000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
16. 16.Find the compound interest on ₹51500 at 20% per year for 3 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹24000 at 15% per year for 2 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹55600 at 5% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹14000 at 20% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹12500 at 20% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 60000 people. The population grows by 5% every year. What will the population be after 2 years?
23. 23.What is the difference between the compound interest and the simple interest on ₹10600 at 20% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹15700 at 10% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹35000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
26. 26.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
28. 28.What amount will ₹30000 grow to in 2 years at 25% per year compound interest (in ₹)?
29. 29.A town has 2500 people. The population grows by 8% every year. What will the population be after 2 years?
30. 30.What amount will ₹45800 grow to in 1 year at 4% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
32. 32.A scooter is worth ₹27500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
34. 34.What amount will ₹29900 grow to in 2 years at 20% per year compound interest (in ₹)?
35. 35.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹28300 at 12% per year for 1 year, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹21600 at 20% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹55600 at 25% per year for 2 years, compounded every year (in ₹).
39. 39.A town has 18000 people. The population grows by 10% every year. What will the population be after 3 years?
40. 40.What amount will ₹10100 grow to in 1 year at 10% per year compound interest (in ₹)?

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