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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 263 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
  2. 2.A scooter is worth ₹35600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  3. 3.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  5. 5.What amount will ₹13100 grow to in 1 year at 25% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹36400 at 8% per year for 1 year, compounded every year (in ₹).
  7. 7.A scooter is worth ₹42000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹26000 at 25% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹18100 at 10% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹23400 at 10% per year for 2 years (in ₹)?
  11. 11.A scooter is worth ₹2900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  12. 12.A town has 3200 people. The population grows by 25% every year. What will the population be after 3 years?
  13. 13.A scooter is worth ₹58800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  14. 14.A scooter is worth ₹14200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  15. 15.A scooter is worth ₹25000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  16. 16.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹12500 at 10% per year for 2 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
  19. 19.What amount will ₹49000 grow to in 3 years at 10% per year compound interest (in ₹)?
  20. 20.Find the compound interest on ₹18000 at 8% per year for 1 year, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹8100 at 10% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹56000 at 25% per year for 2 years (in ₹)?
  23. 23.What amount will ₹44200 grow to in 2 years at 20% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  25. 25.What amount will ₹24000 grow to in 1 year at 15% per year compound interest (in ₹)?
  26. 26.Find the compound interest on ₹31700 at 12% per year for 1 year, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹52800 at 25% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹27000 at 20% per year for 2 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹26800 at 4% per year for 1 year, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹39400 at 20% per year for 1 year, compounded every year (in ₹).
  35. 35.What amount will ₹42500 grow to in 2 years at 4% per year compound interest (in ₹)?
  36. 36.Find the compound interest on ₹10400 at 25% per year for 2 years, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹46400 at 8% per year for 1 year, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
  39. 39.What amount will ₹7700 grow to in 1 year at 20% per year compound interest (in ₹)?
  40. 40.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?

Answer key

  1. 6360
  2. 32129
  3. 20412
  4. 504
  5. 16375
  6. 2912
  7. 30618
  8. 1625
  9. 181
  10. 234
  11. 2349
  12. 6250
  13. 53067
  14. 12496
  15. 18225
  16. 46305
  17. 2625
  18. 112
  19. 65219
  20. 1440
  21. 81
  22. 3500
  23. 63648
  24. 8334
  25. 27600
  26. 3804
  27. 3300
  28. 11880
  29. 1072
  30. 144
  31. 44
  32. 756
  33. 5044
  34. 7880
  35. 45968
  36. 5850
  37. 3712
  38. 408
  39. 9240
  40. 27783

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