Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 2.A town has 18900 people. The population grows by 10% every year. What will the population be after 2 years?
- 3.Find the compound interest on ₹45500 at 10% per year for 1 year, compounded every year (in ₹).
- 4.What is the difference between the compound interest and the simple interest on ₹33800 at 10% per year for 2 years (in ₹)?
- 5.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
- 6.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 7.What amount will ₹26400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹45600 at 5% per year for 2 years (in ₹)?
- 9.What amount will ₹57300 grow to in 1 year at 4% per year compound interest (in ₹)?
- 10.A town has 19200 people. The population grows by 25% every year. What will the population be after 3 years?
- 11.Find the compound interest on ₹48600 at 15% per year for 1 year, compounded every year (in ₹).
- 12.A town has 10000 people. The population grows by 12% every year. What will the population be after 2 years?
- 13.What is the difference between the compound interest and the simple interest on ₹58400 at 25% per year for 2 years (in ₹)?
- 14.A scooter is worth ₹50500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 15.Find the compound interest on ₹8000 at 5% per year for 2 years, compounded every year (in ₹).
- 16.A scooter is worth ₹31200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 17.A scooter is worth ₹59800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 18.Find the compound interest on ₹45000 at 10% per year for 3 years, compounded every year (in ₹).
- 19.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
- 20.A town has 15000 people. The population grows by 4% every year. What will the population be after 2 years?
- 21.A scooter is worth ₹44900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹7300 at 10% per year for 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹16600 at 20% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹41900 at 12% per year for 1 year, compounded every year (in ₹).
- 28.Find the compound interest on ₹17500 at 10% per year for 2 years, compounded every year (in ₹).
- 29.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 30.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
- 31.What is the difference between the compound interest and the simple interest on ₹15200 at 15% per year for 2 years (in ₹)?
- 32.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
- 33.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹35400 at 8% per year for 1 year, compounded every year (in ₹).
- 35.What amount will ₹39400 grow to in 1 year at 5% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹22500 at 20% per year for 3 years, compounded every year (in ₹).
- 37.What amount will ₹31300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 38.A scooter is worth ₹2400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹44000 at 10% per year for 2 years (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹35900 at 10% per year for 2 years (in ₹)?
Answer key
- 416
- 22869
- 4550
- 338
- 1664
- 10816
- 34914
- 114
- 59592
- 37500
- 7290
- 12544
- 3650
- 44440
- 820
- 17550
- 44850
- 14895
- 4284
- 16224
- 36369
- 272
- 73
- 28
- 664
- 2040
- 5028
- 3675
- 21875
- 56425
- 342
- 48668
- 7566
- 2832
- 41370
- 16380
- 34430
- 2166
- 440
- 359
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