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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 267 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
  2. 2.A town has 18900 people. The population grows by 10% every year. What will the population be after 2 years?
  3. 3.Find the compound interest on ₹45500 at 10% per year for 1 year, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹33800 at 10% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
  6. 6.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
  7. 7.What amount will ₹26400 grow to in 2 years at 15% per year compound interest (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹45600 at 5% per year for 2 years (in ₹)?
  9. 9.What amount will ₹57300 grow to in 1 year at 4% per year compound interest (in ₹)?
  10. 10.A town has 19200 people. The population grows by 25% every year. What will the population be after 3 years?
  11. 11.Find the compound interest on ₹48600 at 15% per year for 1 year, compounded every year (in ₹).
  12. 12.A town has 10000 people. The population grows by 12% every year. What will the population be after 2 years?
  13. 13.What is the difference between the compound interest and the simple interest on ₹58400 at 25% per year for 2 years (in ₹)?
  14. 14.A scooter is worth ₹50500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  15. 15.Find the compound interest on ₹8000 at 5% per year for 2 years, compounded every year (in ₹).
  16. 16.A scooter is worth ₹31200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  17. 17.A scooter is worth ₹59800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  18. 18.Find the compound interest on ₹45000 at 10% per year for 3 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
  20. 20.A town has 15000 people. The population grows by 4% every year. What will the population be after 2 years?
  21. 21.A scooter is worth ₹44900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹7300 at 10% per year for 2 years (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹16600 at 20% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹41900 at 12% per year for 1 year, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹17500 at 10% per year for 2 years, compounded every year (in ₹).
  29. 29.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
  31. 31.What is the difference between the compound interest and the simple interest on ₹15200 at 15% per year for 2 years (in ₹)?
  32. 32.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
  33. 33.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹35400 at 8% per year for 1 year, compounded every year (in ₹).
  35. 35.What amount will ₹39400 grow to in 1 year at 5% per year compound interest (in ₹)?
  36. 36.Find the compound interest on ₹22500 at 20% per year for 3 years, compounded every year (in ₹).
  37. 37.What amount will ₹31300 grow to in 1 year at 10% per year compound interest (in ₹)?
  38. 38.A scooter is worth ₹2400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹44000 at 10% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹35900 at 10% per year for 2 years (in ₹)?

Answer key

  1. 416
  2. 22869
  3. 4550
  4. 338
  5. 1664
  6. 10816
  7. 34914
  8. 114
  9. 59592
  10. 37500
  11. 7290
  12. 12544
  13. 3650
  14. 44440
  15. 820
  16. 17550
  17. 44850
  18. 14895
  19. 4284
  20. 16224
  21. 36369
  22. 272
  23. 73
  24. 28
  25. 664
  26. 2040
  27. 5028
  28. 3675
  29. 21875
  30. 56425
  31. 342
  32. 48668
  33. 7566
  34. 2832
  35. 41370
  36. 16380
  37. 34430
  38. 2166
  39. 440
  40. 359

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