Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 268 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
2. 2.A town has 5800 people. The population grows by 8% every year. What will the population be after 1 year?
3. 3.A town has 12200 people. The population grows by 12% every year. What will the population be after 1 year?
4. 4.What is the difference between the compound interest and the simple interest on ₹35700 at 10% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹39600 at 15% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
7. 7.A town has 37700 people. The population grows by 8% every year. What will the population be after 1 year?
8. 8.A scooter is worth ₹16000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
9. 9.What amount will ₹54500 grow to in 1 year at 25% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
11. 11.What amount will ₹34100 grow to in 1 year at 25% per year compound interest (in ₹)?
12. 12.What amount will ₹30000 grow to in 2 years at 12% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹58100 at 10% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹14300 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
17. 17.Find the compound interest on ₹15900 at 20% per year for 1 year, compounded every year (in ₹).
18. 18.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
19. 19.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
20. 20.A scooter is worth ₹31800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
21. 21.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
22. 22.A town has 16100 people. The population grows by 20% every year. What will the population be after 2 years?
23. 23.A town has 19200 people. The population grows by 10% every year. What will the population be after 1 year?
24. 24.What amount will ₹9300 grow to in 1 year at 20% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹26600 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
27. 27.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹51600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
29. 29.What amount will ₹16100 grow to in 1 year at 4% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
32. 32.A town has 46400 people. The population grows by 25% every year. What will the population be after 2 years?
33. 33.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹15500 at 8% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹22200 at 12% per year for 1 year, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹13600 at 15% per year for 2 years (in ₹)?
37. 37.A town has 52800 people. The population grows by 25% every year. What will the population be after 3 years?
38. 38.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹16800 at 15% per year for 2 years (in ₹)?

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