Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 269 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹38300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹8300 at 25% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
5. 5.A scooter is worth ₹36400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
7. 7.What amount will ₹10800 grow to in 2 years at 5% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹32500 at 20% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹25800 at 8% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹14900 at 25% per year for 1 year, compounded every year (in ₹).
11. 11.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
12. 12.A scooter is worth ₹52800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
13. 13.Find the compound interest on ₹53000 at 20% per year for 3 years, compounded every year (in ₹).
14. 14.What amount will ₹11600 grow to in 2 years at 5% per year compound interest (in ₹)?
15. 15.A town has 13000 people. The population grows by 20% every year. What will the population be after 3 years?
16. 16.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
17. 17.A scooter is worth ₹7000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹56000 at 15% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹19000 at 12% per year for 1 year, compounded every year (in ₹).
20. 20.A town has 30600 people. The population grows by 20% every year. What will the population be after 1 year?
21. 21.What amount will ₹5300 grow to in 1 year at 5% per year compound interest (in ₹)?
22. 22.A town has 19600 people. The population grows by 4% every year. What will the population be after 1 year?
23. 23.What is the difference between the compound interest and the simple interest on ₹50000 at 25% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
25. 25.What amount will ₹17600 grow to in 2 years at 5% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
27. 27.What amount will ₹29800 grow to in 1 year at 12% per year compound interest (in ₹)?
28. 28.What amount will ₹48800 grow to in 1 year at 10% per year compound interest (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹19200 at 25% per year for 2 years (in ₹)?
30. 30.What amount will ₹48400 grow to in 1 year at 10% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹14400 at 15% per year for 2 years (in ₹)?
32. 32.A scooter is worth ₹32000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
33. 33.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
34. 34.What amount will ₹17400 grow to in 1 year at 15% per year compound interest (in ₹)?
35. 35.A scooter is worth ₹48100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
36. 36.A town has 40900 people. The population grows by 8% every year. What will the population be after 1 year?
37. 37.A town has 50000 people. The population grows by 12% every year. What will the population be after 2 years?
38. 38.A town has 24900 people. The population grows by 10% every year. What will the population be after 2 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹16800 at 10% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹45000 at 8% per year for 2 years, compounded every year (in ₹).

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