Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 270 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹19600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
2. 2.Find the compound interest on ₹36500 at 10% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹53900 at 20% per year for 2 years, compounded every year (in ₹).
5. 5.What amount will ₹12700 grow to in 1 year at 5% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹41000 at 10% per year for 3 years, compounded every year (in ₹).
7. 7.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?
8. 8.A scooter is worth ₹37500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
9. 9.Find the compound interest on ₹2500 at 8% per year for 1 year, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹19600 at 5% per year for 2 years (in ₹)?
11. 11.What amount will ₹32100 grow to in 1 year at 5% per year compound interest (in ₹)?
12. 12.A town has 57900 people. The population grows by 10% every year. What will the population be after 1 year?
13. 13.What is the difference between the compound interest and the simple interest on ₹13400 at 10% per year for 2 years (in ₹)?
14. 14.What amount will ₹9100 grow to in 1 year at 4% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹25600 at 20% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
17. 17.A town has 54200 people. The population grows by 4% every year. What will the population be after 1 year?
18. 18.What amount will ₹34400 grow to in 2 years at 25% per year compound interest (in ₹)?
19. 19.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
20. 20.Find the compound interest on ₹18600 at 12% per year for 1 year, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹19100 at 20% per year for 2 years (in ₹)?
22. 22.A town has 5000 people. The population grows by 10% every year. What will the population be after 3 years?
23. 23.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹56900 at 25% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹9300 grow to in 2 years at 10% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹14500 at 10% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹42900 at 10% per year for 1 year, compounded every year (in ₹).
29. 29.A town has 19900 people. The population grows by 10% every year. What will the population be after 1 year?
30. 30.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
31. 31.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹12800 at 25% per year for 3 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹56700 at 4% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹44000 grow to in 2 years at 10% per year compound interest (in ₹)?
35. 35.What amount will ₹48300 grow to in 1 year at 8% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹35200 at 20% per year for 1 year, compounded every year (in ₹).
37. 37.A scooter is worth ₹33400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
38. 38.What amount will ₹25000 grow to in 3 years at 20% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
40. 40.What amount will ₹11500 grow to in 1 year at 4% per year compound interest (in ₹)?

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