Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 28 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹47500 at 4% per year for 2 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹54300 at 25% per year for 1 year, compounded every year (in ₹).
3. 3.A town has 11100 people. The population grows by 20% every year. What will the population be after 2 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
5. 5.What amount will ₹24700 grow to in 2 years at 10% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
7. 7.A town has 10600 people. The population grows by 20% every year. What will the population be after 1 year?
8. 8.What is the difference between the compound interest and the simple interest on ₹46600 at 10% per year for 2 years (in ₹)?
9. 9.What amount will ₹3500 grow to in 1 year at 20% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
11. 11.What amount will ₹7300 grow to in 2 years at 20% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
13. 13.What amount will ₹40000 grow to in 2 years at 5% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
15. 15.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
16. 16.What amount will ₹3600 grow to in 1 year at 25% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹40300 at 10% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹22600 at 10% per year for 2 years, compounded every year (in ₹).
19. 19.Find the compound interest on ₹37100 at 20% per year for 2 years, compounded every year (in ₹).
20. 20.What amount will ₹52200 grow to in 1 year at 25% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹16400 at 12% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 33500 people. The population grows by 8% every year. What will the population be after 1 year?
23. 23.A town has 29000 people. The population grows by 10% every year. What will the population be after 3 years?
24. 24.A town has 11200 people. The population grows by 5% every year. What will the population be after 1 year?
25. 25.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹51600 at 5% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹12500 at 20% per year for 3 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹43200 at 25% per year for 2 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹41500 at 10% per year for 2 years (in ₹)?
31. 31.A town has 32500 people. The population grows by 8% every year. What will the population be after 2 years?
32. 32.Find the compound interest on ₹30400 at 25% per year for 2 years, compounded every year (in ₹).
33. 33.A town has 35200 people. The population grows by 15% every year. What will the population be after 2 years?
34. 34.A scooter is worth ₹20500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
36. 36.A town has 14900 people. The population grows by 4% every year. What will the population be after 1 year?
37. 37.A scooter is worth ₹58400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
38. 38.A scooter is worth ₹34100. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
39. 39.A scooter is worth ₹7300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
40. 40.What amount will ₹52800 grow to in 1 year at 8% per year compound interest (in ₹)?

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