Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 274 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹55000 grow to in 3 years at 10% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹42700 at 10% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹26000 at 25% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
5. 5.A town has 53000 people. The population grows by 20% every year. What will the population be after 3 years?
6. 6.What amount will ₹4000 grow to in 2 years at 5% per year compound interest (in ₹)?
7. 7.A town has 2500 people. The population grows by 8% every year. What will the population be after 2 years?
8. 8.What amount will ₹42300 grow to in 1 year at 20% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹35100 at 5% per year for 1 year, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹29200 at 20% per year for 2 years (in ₹)?
11. 11.A town has 2000 people. The population grows by 10% every year. What will the population be after 3 years?
12. 12.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
14. 14.A scooter is worth ₹57600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
15. 15.Find the compound interest on ₹41500 at 20% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹48000 grow to in 1 year at 20% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹18000 at 20% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹33500 at 25% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹7200 at 15% per year for 2 years (in ₹)?
21. 21.A scooter is worth ₹46900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
22. 22.A scooter is worth ₹16000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
23. 23.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹35300 at 10% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹24100 at 12% per year for 1 year, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹2200 at 10% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
28. 28.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
29. 29.What amount will ₹37000 grow to in 3 years at 10% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹38900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
32. 32.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹44800 at 25% per year for 2 years (in ₹)?
34. 34.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
35. 35.A scooter is worth ₹2000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹28700 at 20% per year for 2 years (in ₹)?
37. 37.Find the compound interest on ₹10300 at 10% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
39. 39.A scooter is worth ₹18500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
40. 40.Find the compound interest on ₹44000 at 20% per year for 3 years, compounded every year (in ₹).

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