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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 275 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹7200 at 10% per year for 1 year, compounded every year (in ₹).
  2. 2.A scooter is worth ₹16000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  3. 3.Find the compound interest on ₹57400 at 25% per year for 1 year, compounded every year (in ₹).
  4. 4.What amount will ₹42500 grow to in 2 years at 4% per year compound interest (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
  6. 6.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹7000 at 20% per year for 2 years (in ₹)?
  9. 9.What amount will ₹31100 grow to in 1 year at 12% per year compound interest (in ₹)?
  10. 10.A town has 39900 people. The population grows by 25% every year. What will the population be after 1 year?
  11. 11.A scooter is worth ₹39800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  12. 12.Find the compound interest on ₹6800 at 15% per year for 2 years, compounded every year (in ₹).
  13. 13.A town has 17900 people. The population grows by 12% every year. What will the population be after 1 year?
  14. 14.What is the difference between the compound interest and the simple interest on ₹28000 at 15% per year for 2 years (in ₹)?
  15. 15.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
  17. 17.What amount will ₹26400 grow to in 2 years at 5% per year compound interest (in ₹)?
  18. 18.What amount will ₹50000 grow to in 2 years at 25% per year compound interest (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  20. 20.What amount will ₹51400 grow to in 1 year at 8% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹54000 at 5% per year for 2 years (in ₹)?
  22. 22.A scooter is worth ₹32100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  23. 23.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  25. 25.What amount will ₹41200 grow to in 2 years at 5% per year compound interest (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹12100 at 10% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹23200 at 5% per year for 2 years (in ₹)?
  29. 29.Find the compound interest on ₹51800 at 5% per year for 1 year, compounded every year (in ₹).
  30. 30.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
  31. 31.Find the compound interest on ₹24700 at 5% per year for 1 year, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹46300 at 15% per year for 1 year, compounded every year (in ₹).
  33. 33.A scooter is worth ₹58000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  34. 34.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
  35. 35.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
  36. 36.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
  37. 37.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
  38. 38.What amount will ₹12800 grow to in 2 years at 25% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  40. 40.A town has 2200 people. The population grows by 8% every year. What will the population be after 1 year?

Answer key

  1. 720
  2. 6750
  3. 14350
  4. 45968
  5. 256
  6. 21160
  7. 128
  8. 280
  9. 34832
  10. 49875
  11. 35820
  12. 2193
  13. 20048
  14. 630
  15. 64827
  16. 105
  17. 29106
  18. 78125
  19. 504
  20. 55512
  21. 135
  22. 25680
  23. 10923
  24. 6305
  25. 45423
  26. 121
  27. 4167
  28. 58
  29. 2590
  30. 55404
  31. 1235
  32. 6945
  33. 41905
  34. 2080
  35. 73002
  36. 72128
  37. 1664
  38. 20000
  39. 7566
  40. 2376

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