Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹7200 at 10% per year for 1 year, compounded every year (in ₹).
- 2.A scooter is worth ₹16000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 3.Find the compound interest on ₹57400 at 25% per year for 1 year, compounded every year (in ₹).
- 4.What amount will ₹42500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
- 6.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹7000 at 20% per year for 2 years (in ₹)?
- 9.What amount will ₹31100 grow to in 1 year at 12% per year compound interest (in ₹)?
- 10.A town has 39900 people. The population grows by 25% every year. What will the population be after 1 year?
- 11.A scooter is worth ₹39800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 12.Find the compound interest on ₹6800 at 15% per year for 2 years, compounded every year (in ₹).
- 13.A town has 17900 people. The population grows by 12% every year. What will the population be after 1 year?
- 14.What is the difference between the compound interest and the simple interest on ₹28000 at 15% per year for 2 years (in ₹)?
- 15.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
- 17.What amount will ₹26400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 18.What amount will ₹50000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
- 20.What amount will ₹51400 grow to in 1 year at 8% per year compound interest (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹54000 at 5% per year for 2 years (in ₹)?
- 22.A scooter is worth ₹32100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 23.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 25.What amount will ₹41200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹12100 at 10% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 28.What is the difference between the compound interest and the simple interest on ₹23200 at 5% per year for 2 years (in ₹)?
- 29.Find the compound interest on ₹51800 at 5% per year for 1 year, compounded every year (in ₹).
- 30.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
- 31.Find the compound interest on ₹24700 at 5% per year for 1 year, compounded every year (in ₹).
- 32.Find the compound interest on ₹46300 at 15% per year for 1 year, compounded every year (in ₹).
- 33.A scooter is worth ₹58000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 34.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
- 35.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 36.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
- 37.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
- 38.What amount will ₹12800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 40.A town has 2200 people. The population grows by 8% every year. What will the population be after 1 year?
Answer key
- 720
- 6750
- 14350
- 45968
- 256
- 21160
- 128
- 280
- 34832
- 49875
- 35820
- 2193
- 20048
- 630
- 64827
- 105
- 29106
- 78125
- 504
- 55512
- 135
- 25680
- 10923
- 6305
- 45423
- 121
- 4167
- 58
- 2590
- 55404
- 1235
- 6945
- 41905
- 2080
- 73002
- 72128
- 1664
- 20000
- 7566
- 2376
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