Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 276 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 37600 people. The population grows by 5% every year. What will the population be after 2 years?
2. 2.A scooter is worth ₹45000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
3. 3.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 20500 people. The population grows by 12% every year. What will the population be after 1 year?
6. 6.A town has 40000 people. The population grows by 25% every year. What will the population be after 3 years?
7. 7.Find the compound interest on ₹25400 at 15% per year for 1 year, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
10. 10.A scooter is worth ₹15600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
11. 11.What amount will ₹28800 grow to in 3 years at 25% per year compound interest (in ₹)?
12. 12.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
13. 13.A scooter is worth ₹56300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
14. 14.Find the compound interest on ₹31500 at 20% per year for 1 year, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹4800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
17. 17.Find the compound interest on ₹4500 at 8% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹56800 at 5% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹33600 at 25% per year for 2 years (in ₹)?
20. 20.A town has 6100 people. The population grows by 5% every year. What will the population be after 1 year?
21. 21.Find the compound interest on ₹9000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.A town has 42500 people. The population grows by 12% every year. What will the population be after 2 years?
23. 23.Find the compound interest on ₹11400 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.Find the compound interest on ₹6900 at 4% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹42200 at 25% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹55600 at 20% per year for 1 year, compounded every year (in ₹).
27. 27.What amount will ₹2600 grow to in 1 year at 15% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹54800 at 15% per year for 2 years (in ₹)?
30. 30.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
31. 31.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
32. 32.A town has 59900 people. The population grows by 5% every year. What will the population be after 1 year?
33. 33.What amount will ₹11600 grow to in 2 years at 25% per year compound interest (in ₹)?
34. 34.What amount will ₹53800 grow to in 1 year at 12% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹5200 at 4% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹18000 grow to in 1 year at 5% per year compound interest (in ₹)?
37. 37.A town has 46800 people. The population grows by 5% every year. What will the population be after 2 years?
38. 38.What amount will ₹3100 grow to in 2 years at 10% per year compound interest (in ₹)?
39. 39.What amount will ₹29300 grow to in 1 year at 25% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹37500 at 12% per year for 2 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets