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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 277 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 43400 people. The population grows by 8% every year. What will the population be after 1 year?
  2. 2.What amount will ₹42000 grow to in 1 year at 8% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  4. 4.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
  5. 5.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹55600 at 5% per year for 2 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
  9. 9.A scooter is worth ₹31100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  10. 10.Find the compound interest on ₹56600 at 20% per year for 1 year, compounded every year (in ₹).
  11. 11.A scooter is worth ₹28000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  12. 12.Find the compound interest on ₹18000 at 10% per year for 1 year, compounded every year (in ₹).
  13. 13.What amount will ₹34600 grow to in 2 years at 20% per year compound interest (in ₹)?
  14. 14.What amount will ₹27600 grow to in 2 years at 5% per year compound interest (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹9900 at 10% per year for 2 years (in ₹)?
  16. 16.Find the compound interest on ₹23600 at 8% per year for 1 year, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹20800 at 25% per year for 3 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹29300 at 10% per year for 1 year, compounded every year (in ₹).
  20. 20.A town has 6400 people. The population grows by 25% every year. What will the population be after 3 years?
  21. 21.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
  22. 22.Find the compound interest on ₹28800 at 25% per year for 2 years, compounded every year (in ₹).
  23. 23.A town has 59600 people. The population grows by 15% every year. What will the population be after 2 years?
  24. 24.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
  25. 25.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
  26. 26.Find the compound interest on ₹33300 at 8% per year for 1 year, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹34400 at 15% per year for 2 years, compounded every year (in ₹).
  28. 28.What amount will ₹11600 grow to in 1 year at 4% per year compound interest (in ₹)?
  29. 29.What amount will ₹43100 grow to in 2 years at 10% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹23000 at 10% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹29100 at 5% per year for 1 year, compounded every year (in ₹).
  33. 33.What amount will ₹58800 grow to in 1 year at 12% per year compound interest (in ₹)?
  34. 34.A town has 29300 people. The population grows by 4% every year. What will the population be after 1 year?
  35. 35.Find the compound interest on ₹17000 at 20% per year for 3 years, compounded every year (in ₹).
  36. 36.What amount will ₹20600 grow to in 2 years at 10% per year compound interest (in ₹)?
  37. 37.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹35900 at 10% per year for 2 years, compounded every year (in ₹).
  39. 39.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  40. 40.A scooter is worth ₹47700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 46872
  2. 45360
  3. 6305
  4. 73002
  5. 18522
  6. 92
  7. 5699
  8. 288
  9. 25191
  10. 11320
  11. 20412
  12. 1800
  13. 49824
  14. 30429
  15. 99
  16. 1888
  17. 19825
  18. 96
  19. 2930
  20. 12500
  21. 27783
  22. 16200
  23. 78821
  24. 59488
  25. 40768
  26. 2664
  27. 11094
  28. 12064
  29. 52151
  30. 105
  31. 230
  32. 1455
  33. 65856
  34. 30472
  35. 12376
  36. 24926
  37. 47040
  38. 7539
  39. 41154
  40. 41976

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