Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.A town has 43400 people. The population grows by 8% every year. What will the population be after 1 year?
- 2.What amount will ₹42000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 4.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 5.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹55600 at 5% per year for 2 years, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
- 9.A scooter is worth ₹31100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 10.Find the compound interest on ₹56600 at 20% per year for 1 year, compounded every year (in ₹).
- 11.A scooter is worth ₹28000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 12.Find the compound interest on ₹18000 at 10% per year for 1 year, compounded every year (in ₹).
- 13.What amount will ₹34600 grow to in 2 years at 20% per year compound interest (in ₹)?
- 14.What amount will ₹27600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹9900 at 10% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹23600 at 8% per year for 1 year, compounded every year (in ₹).
- 17.Find the compound interest on ₹20800 at 25% per year for 3 years, compounded every year (in ₹).
- 18.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹29300 at 10% per year for 1 year, compounded every year (in ₹).
- 20.A town has 6400 people. The population grows by 25% every year. What will the population be after 3 years?
- 21.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
- 22.Find the compound interest on ₹28800 at 25% per year for 2 years, compounded every year (in ₹).
- 23.A town has 59600 people. The population grows by 15% every year. What will the population be after 2 years?
- 24.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 25.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
- 26.Find the compound interest on ₹33300 at 8% per year for 1 year, compounded every year (in ₹).
- 27.Find the compound interest on ₹34400 at 15% per year for 2 years, compounded every year (in ₹).
- 28.What amount will ₹11600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 29.What amount will ₹43100 grow to in 2 years at 10% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹23000 at 10% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹29100 at 5% per year for 1 year, compounded every year (in ₹).
- 33.What amount will ₹58800 grow to in 1 year at 12% per year compound interest (in ₹)?
- 34.A town has 29300 people. The population grows by 4% every year. What will the population be after 1 year?
- 35.Find the compound interest on ₹17000 at 20% per year for 3 years, compounded every year (in ₹).
- 36.What amount will ₹20600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 37.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹35900 at 10% per year for 2 years, compounded every year (in ₹).
- 39.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 40.A scooter is worth ₹47700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
Answer key
- 46872
- 45360
- 6305
- 73002
- 18522
- 92
- 5699
- 288
- 25191
- 11320
- 20412
- 1800
- 49824
- 30429
- 99
- 1888
- 19825
- 96
- 2930
- 12500
- 27783
- 16200
- 78821
- 59488
- 40768
- 2664
- 11094
- 12064
- 52151
- 105
- 230
- 1455
- 65856
- 30472
- 12376
- 24926
- 47040
- 7539
- 41154
- 41976
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