Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 285 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
2. 2.What is the difference between the compound interest and the simple interest on ₹8800 at 25% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹57700 at 20% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹29600 at 25% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
6. 6.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
7. 7.What amount will ₹18500 grow to in 3 years at 20% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹17900 at 5% per year for 1 year, compounded every year (in ₹).
9. 9.Find the compound interest on ₹25700 at 15% per year for 1 year, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹50000 at 25% per year for 2 years (in ₹)?
12. 12.What amount will ₹43700 grow to in 1 year at 20% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹32800 at 25% per year for 2 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹27300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
17. 17.What amount will ₹9800 grow to in 1 year at 8% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹45600 at 15% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹32200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
21. 21.What amount will ₹19800 grow to in 1 year at 15% per year compound interest (in ₹)?
22. 22.A town has 46400 people. The population grows by 15% every year. What will the population be after 2 years?
23. 23.What is the difference between the compound interest and the simple interest on ₹58200 at 10% per year for 2 years (in ₹)?
24. 24.A scooter is worth ₹54200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
25. 25.A town has 38200 people. The population grows by 5% every year. What will the population be after 1 year?
26. 26.Find the compound interest on ₹51600 at 15% per year for 2 years, compounded every year (in ₹).
27. 27.What amount will ₹7000 grow to in 3 years at 10% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹16700 at 5% per year for 1 year, compounded every year (in ₹).
29. 29.What amount will ₹13900 grow to in 1 year at 15% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹42500 at 15% per year for 1 year, compounded every year (in ₹).
31. 31.Find the compound interest on ₹24500 at 10% per year for 2 years, compounded every year (in ₹).
32. 32.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
33. 33.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
34. 34.What amount will ₹17500 grow to in 2 years at 12% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹53600 at 20% per year for 1 year, compounded every year (in ₹).
36. 36.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
37. 37.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹52600. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
40. 40.Find the compound interest on ₹32100 at 4% per year for 1 year, compounded every year (in ₹).

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