← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 288 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹20800 at 15% per year for 2 years, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹58100 at 10% per year for 1 year, compounded every year (in ₹).
  3. 3.A scooter is worth ₹9000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  4. 4.A town has 49400 people. The population grows by 25% every year. What will the population be after 1 year?
  5. 5.A town has 20700 people. The population grows by 8% every year. What will the population be after 1 year?
  6. 6.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹31200 at 20% per year for 2 years (in ₹)?
  8. 8.A scooter is worth ₹59200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  9. 9.What amount will ₹19100 grow to in 1 year at 20% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹10000 at 5% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹13600 at 15% per year for 2 years (in ₹)?
  12. 12.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
  13. 13.A town has 51200 people. The population grows by 25% every year. What will the population be after 3 years?
  14. 14.Find the compound interest on ₹5400 at 25% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹16800 at 25% per year for 2 years (in ₹)?
  16. 16.What amount will ₹34000 grow to in 2 years at 10% per year compound interest (in ₹)?
  17. 17.What amount will ₹50700 grow to in 1 year at 4% per year compound interest (in ₹)?
  18. 18.What amount will ₹5200 grow to in 2 years at 15% per year compound interest (in ₹)?
  19. 19.What amount will ₹34800 grow to in 1 year at 10% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹11700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  21. 21.What amount will ₹43300 grow to in 1 year at 15% per year compound interest (in ₹)?
  22. 22.Find the compound interest on ₹8700 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.What amount will ₹33700 grow to in 2 years at 10% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹13200 at 5% per year for 2 years, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹36800 at 20% per year for 1 year, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
  27. 27.A scooter is worth ₹32000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  28. 28.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹15000 at 8% per year for 2 years, compounded every year (in ₹).
  30. 30.What amount will ₹25100 grow to in 1 year at 12% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹23600 at 20% per year for 2 years (in ₹)?
  32. 32.A scooter is worth ₹36400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  33. 33.Find the compound interest on ₹30500 at 20% per year for 1 year, compounded every year (in ₹).
  34. 34.What amount will ₹54900 grow to in 1 year at 5% per year compound interest (in ₹)?
  35. 35.A scooter is worth ₹25600. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  36. 36.What amount will ₹11700 grow to in 1 year at 20% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹14800 at 20% per year for 2 years, compounded every year (in ₹).
  38. 38.What amount will ₹17100 grow to in 1 year at 4% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹31000 at 10% per year for 2 years, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?

Answer key

  1. 6708
  2. 5810
  3. 6561
  4. 61750
  5. 22356
  6. 828
  7. 1248
  8. 24975
  9. 22920
  10. 1025
  11. 306
  12. 31250
  13. 100000
  14. 1350
  15. 1050
  16. 41140
  17. 52728
  18. 6877
  19. 38280
  20. 10530
  21. 49795
  22. 870
  23. 40777
  24. 1353
  25. 7360
  26. 5724
  27. 13500
  28. 5044
  29. 2496
  30. 28112
  31. 944
  32. 32851
  33. 6100
  34. 57645
  35. 22528
  36. 14040
  37. 6512
  38. 17784
  39. 6510
  40. 76

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets