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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 297 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
  2. 2.What amount will ₹59500 grow to in 1 year at 5% per year compound interest (in ₹)?
  3. 3.What amount will ₹10700 grow to in 1 year at 4% per year compound interest (in ₹)?
  4. 4.What amount will ₹43000 grow to in 3 years at 20% per year compound interest (in ₹)?
  5. 5.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  7. 7.A town has 8500 people. The population grows by 20% every year. What will the population be after 3 years?
  8. 8.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  9. 9.A town has 15000 people. The population grows by 20% every year. What will the population be after 1 year?
  10. 10.Find the compound interest on ₹32500 at 8% per year for 2 years, compounded every year (in ₹).
  11. 11.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
  12. 12.Find the compound interest on ₹40800 at 8% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹27200 at 15% per year for 2 years (in ₹)?
  14. 14.What amount will ₹8100 grow to in 2 years at 10% per year compound interest (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  16. 16.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  17. 17.What amount will ₹15300 grow to in 1 year at 8% per year compound interest (in ₹)?
  18. 18.A scooter is worth ₹12500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  19. 19.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹30400 at 20% per year for 2 years (in ₹)?
  21. 21.A scooter is worth ₹27000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹52800 at 5% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹41500 at 4% per year for 1 year, compounded every year (in ₹).
  24. 24.What amount will ₹47800 grow to in 2 years at 10% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹39600 at 25% per year for 2 years, compounded every year (in ₹).
  26. 26.A scooter is worth ₹35000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹36900 at 20% per year for 2 years (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹8400 at 25% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹52000 at 25% per year for 2 years (in ₹)?
  30. 30.A scooter is worth ₹32200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  31. 31.A town has 14900 people. The population grows by 4% every year. What will the population be after 1 year?
  32. 32.What amount will ₹34600 grow to in 1 year at 10% per year compound interest (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹32800 at 10% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹5000 at 20% per year for 1 year, compounded every year (in ₹).
  35. 35.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹21200 at 5% per year for 2 years (in ₹)?
  37. 37.A town has 40000 people. The population grows by 12% every year. What will the population be after 2 years?
  38. 38.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
  39. 39.What amount will ₹44600 grow to in 2 years at 20% per year compound interest (in ₹)?
  40. 40.What amount will ₹11600 grow to in 2 years at 5% per year compound interest (in ₹)?

Answer key

  1. 7072
  2. 62475
  3. 11128
  4. 74304
  5. 29160
  6. 4167
  7. 14688
  8. 29478
  9. 18000
  10. 5408
  11. 54080
  12. 3264
  13. 612
  14. 9801
  15. 192
  16. 18522
  17. 16524
  18. 11520
  19. 37908
  20. 1216
  21. 13824
  22. 132
  23. 1660
  24. 57838
  25. 22275
  26. 32256
  27. 1476
  28. 525
  29. 3250
  30. 30912
  31. 15496
  32. 38060
  33. 328
  34. 1000
  35. 54571
  36. 53
  37. 50176
  38. 33550
  39. 64224
  40. 12789

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