Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 298 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹9800 at 20% per year for 2 years (in ₹)?
3. 3.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹19700 at 5% per year for 1 year, compounded every year (in ₹).
5. 5.A scooter is worth ₹41100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
6. 6.A town has 24400 people. The population grows by 25% every year. What will the population be after 2 years?
7. 7.A scooter is worth ₹45800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
8. 8.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹23700 at 12% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹37400 at 10% per year for 1 year, compounded every year (in ₹).
13. 13.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
14. 14.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
15. 15.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
18. 18.A town has 29600 people. The population grows by 5% every year. What will the population be after 2 years?
19. 19.A town has 45000 people. The population grows by 12% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹20900 at 5% per year for 1 year, compounded every year (in ₹).
21. 21.What amount will ₹8000 grow to in 2 years at 15% per year compound interest (in ₹)?
22. 22.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
23. 23.A town has 30800 people. The population grows by 25% every year. What will the population be after 1 year?
24. 24.What is the difference between the compound interest and the simple interest on ₹10800 at 5% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹23300 at 10% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹24300 at 15% per year for 1 year, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹20700 at 10% per year for 2 years (in ₹)?
28. 28.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
29. 29.What amount will ₹9200 grow to in 2 years at 5% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹28400 at 25% per year for 2 years (in ₹)?
31. 31.A town has 56200 people. The population grows by 4% every year. What will the population be after 1 year?
32. 32.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
33. 33.A scooter is worth ₹22400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
34. 34.Find the compound interest on ₹15700 at 10% per year for 1 year, compounded every year (in ₹).
35. 35.A scooter is worth ₹21900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹7600 at 10% per year for 2 years (in ₹)?
37. 37.What amount will ₹5600 grow to in 2 years at 5% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹19900 at 5% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹45900 at 20% per year for 1 year, compounded every year (in ₹).

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