Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 299 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹47400 grow to in 1 year at 25% per year compound interest (in ₹)?
2. 2.What amount will ₹53400 grow to in 1 year at 12% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹53200 at 10% per year for 2 years (in ₹)?
4. 4.What amount will ₹25300 grow to in 1 year at 8% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
6. 6.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
7. 7.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
8. 8.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
9. 9.Find the compound interest on ₹11600 at 5% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹47200 at 5% per year for 2 years, compounded every year (in ₹).
11. 11.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹23100 at 20% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
14. 14.What amount will ₹26000 grow to in 3 years at 20% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹12600 at 10% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹16100 at 10% per year for 2 years (in ₹)?
17. 17.What amount will ₹10000 grow to in 2 years at 25% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹6000 at 5% per year for 2 years, compounded every year (in ₹).
19. 19.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹22500 at 8% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹35900 grow to in 1 year at 25% per year compound interest (in ₹)?
22. 22.A town has 4100 people. The population grows by 5% every year. What will the population be after 1 year?
23. 23.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹34900 at 15% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹54900 at 10% per year for 2 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
27. 27.A scooter is worth ₹39100. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
28. 28.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
30. 30.A scooter is worth ₹7500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
31. 31.A scooter is worth ₹58100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
32. 32.A scooter is worth ₹37500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
33. 33.What amount will ₹34000 grow to in 2 years at 25% per year compound interest (in ₹)?
34. 34.What amount will ₹15100 grow to in 2 years at 10% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹21200 at 15% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹54000 at 15% per year for 2 years, compounded every year (in ₹).
38. 38.A town has 52000 people. The population grows by 15% every year. What will the population be after 2 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹7200 at 15% per year for 2 years (in ₹)?
40. 40.A scooter is worth ₹29600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?

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