Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 303 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
3. 3.What amount will ₹22800 grow to in 2 years at 25% per year compound interest (in ₹)?
4. 4.What amount will ₹54200 grow to in 1 year at 10% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹45400 at 20% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹10000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
9. 9.What amount will ₹7500 grow to in 1 year at 4% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹5400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
11. 11.Find the compound interest on ₹14400 at 10% per year for 2 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹47000 at 10% per year for 3 years, compounded every year (in ₹).
14. 14.A town has 17900 people. The population grows by 10% every year. What will the population be after 1 year?
15. 15.What is the difference between the compound interest and the simple interest on ₹10800 at 15% per year for 2 years (in ₹)?
16. 16.A town has 8000 people. The population grows by 10% every year. What will the population be after 3 years?
17. 17.What amount will ₹3900 grow to in 2 years at 20% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹12000 at 10% per year for 2 years, compounded every year (in ₹).
19. 19.Find the compound interest on ₹39000 at 8% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹30500 at 10% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹54400 at 4% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 52000 people. The population grows by 25% every year. What will the population be after 2 years?
23. 23.Find the compound interest on ₹2000 at 15% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹45200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
27. 27.Find the compound interest on ₹6000 at 5% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹44800 at 5% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹57500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
30. 30.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
31. 31.A scooter is worth ₹18900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹16400 at 5% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹10000 at 20% per year for 3 years, compounded every year (in ₹).
34. 34.A town has 14400 people. The population grows by 25% every year. What will the population be after 3 years?
35. 35.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.What amount will ₹28800 grow to in 2 years at 15% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹47600 at 5% per year for 2 years, compounded every year (in ₹).
39. 39.A town has 28500 people. The population grows by 20% every year. What will the population be after 1 year?
40. 40.What amount will ₹33000 grow to in 3 years at 10% per year compound interest (in ₹)?

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