Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 306 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹56000 grow to in 3 years at 10% per year compound interest (in ₹)?
2. 2.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
3. 3.Find the compound interest on ₹41200 at 5% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
5. 5.A scooter is worth ₹50900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹32800 at 5% per year for 2 years (in ₹)?
7. 7.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
8. 8.A town has 25000 people. The population grows by 4% every year. What will the population be after 2 years?
9. 9.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
10. 10.What amount will ₹16300 grow to in 1 year at 10% per year compound interest (in ₹)?
11. 11.What amount will ₹33200 grow to in 1 year at 10% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹12100 at 5% per year for 1 year, compounded every year (in ₹).
13. 13.What amount will ₹22000 grow to in 2 years at 15% per year compound interest (in ₹)?
14. 14.A scooter is worth ₹22400. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹33600 at 25% per year for 2 years (in ₹)?
18. 18.What amount will ₹12000 grow to in 3 years at 10% per year compound interest (in ₹)?
19. 19.What amount will ₹19900 grow to in 1 year at 4% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹13200 at 25% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹44000 at 15% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
24. 24.What amount will ₹52000 grow to in 3 years at 10% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
26. 26.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹43200 at 5% per year for 2 years (in ₹)?
28. 28.A town has 51100 people. The population grows by 5% every year. What will the population be after 1 year?
29. 29.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
30. 30.What is the difference between the compound interest and the simple interest on ₹57700 at 10% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹2400 at 15% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹56400 at 5% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹7600 at 15% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
35. 35.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
36. 36.What amount will ₹32900 grow to in 1 year at 5% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹59600 at 10% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹12000 at 25% per year for 2 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹46700 at 12% per year for 1 year, compounded every year (in ₹).
40. 40.A town has 42500 people. The population grows by 4% every year. What will the population be after 2 years?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets