Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 309 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹26500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
2. 2.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
3. 3.What amount will ₹30900 grow to in 2 years at 10% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹31100 at 25% per year for 1 year, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹42000 at 10% per year for 3 years, compounded every year (in ₹).
7. 7.A scooter is worth ₹32500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
8. 8.Find the compound interest on ₹16100 at 5% per year for 1 year, compounded every year (in ₹).
9. 9.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
10. 10.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹11600 at 8% per year for 1 year, compounded every year (in ₹).
12. 12.A town has 35000 people. The population grows by 4% every year. What will the population be after 2 years?
13. 13.A town has 38300 people. The population grows by 4% every year. What will the population be after 1 year?
14. 14.A scooter is worth ₹44100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
15. 15.Find the compound interest on ₹29000 at 20% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹57300 at 20% per year for 2 years, compounded every year (in ₹).
17. 17.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
18. 18.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
19. 19.Find the compound interest on ₹45700 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹12000 at 25% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹52700 grow to in 1 year at 8% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹50000 at 5% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
24. 24.What amount will ₹35000 grow to in 2 years at 10% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹44000 at 20% per year for 3 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹56000 at 4% per year for 1 year, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹49600 at 5% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹17700 at 5% per year for 1 year, compounded every year (in ₹).
29. 29.What amount will ₹56300 grow to in 1 year at 5% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹4800 at 5% per year for 2 years, compounded every year (in ₹).
31. 31.A scooter is worth ₹34900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹32400 at 15% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
34. 34.What amount will ₹46000 grow to in 2 years at 25% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
36. 36.A scooter is worth ₹48600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
37. 37.What amount will ₹26000 grow to in 2 years at 5% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹35000 at 4% per year for 2 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹35200 at 10% per year for 2 years (in ₹)?
40. 40.A scooter is worth ₹54800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?

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