Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹14200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
- 3.A scooter is worth ₹42000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 4.Find the compound interest on ₹25300 at 10% per year for 1 year, compounded every year (in ₹).
- 5.What amount will ₹55900 grow to in 1 year at 5% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹50000 at 10% per year for 3 years, compounded every year (in ₹).
- 7.What amount will ₹11800 grow to in 1 year at 4% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹14900 at 10% per year for 2 years, compounded every year (in ₹).
- 9.A town has 26100 people. The population grows by 20% every year. What will the population be after 1 year?
- 10.Find the compound interest on ₹50800 at 10% per year for 1 year, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
- 12.Find the compound interest on ₹37200 at 15% per year for 2 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹30700 at 5% per year for 1 year, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹27200 at 25% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 17.A town has 53000 people. The population grows by 10% every year. What will the population be after 2 years?
- 18.A scooter is worth ₹34300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹58000 at 15% per year for 2 years (in ₹)?
- 20.A town has 58000 people. The population grows by 10% every year. What will the population be after 1 year?
- 21.Find the compound interest on ₹53700 at 8% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹44700 at 10% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
- 26.What amount will ₹20100 grow to in 1 year at 8% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹44900 at 10% per year for 1 year, compounded every year (in ₹).
- 28.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹8800 at 25% per year for 2 years (in ₹)?
- 30.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 31.What is the difference between the compound interest and the simple interest on ₹32000 at 10% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹33000 at 20% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹19000 at 5% per year for 1 year, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹25600 at 25% per year for 2 years (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹52400 at 15% per year for 2 years (in ₹)?
- 36.What amount will ₹12500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 37.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹27600 at 5% per year for 2 years, compounded every year (in ₹).
- 39.A town has 12800 people. The population grows by 25% every year. What will the population be after 3 years?
- 40.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
Answer key
- 15620
- 80
- 21504
- 2530
- 58695
- 16550
- 12272
- 3129
- 31320
- 5080
- 96
- 11997
- 1535
- 32
- 1700
- 6305
- 64130
- 30870
- 1305
- 63800
- 4296
- 447
- 3264
- 180
- 864
- 21708
- 4490
- 13718
- 550
- 18522
- 320
- 1320
- 950
- 1600
- 1179
- 13750
- 11664
- 2829
- 25000
- 68
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