Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 311 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹42800 grow to in 1 year at 10% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹11000 at 15% per year for 1 year, compounded every year (in ₹).
3. 3.Find the compound interest on ₹52400 at 25% per year for 2 years, compounded every year (in ₹).
4. 4.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
5. 5.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹22000 at 5% per year for 2 years (in ₹)?
7. 7.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
8. 8.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
9. 9.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
11. 11.What amount will ₹19200 grow to in 1 year at 4% per year compound interest (in ₹)?
12. 12.What amount will ₹56800 grow to in 2 years at 5% per year compound interest (in ₹)?
13. 13.A town has 9200 people. The population grows by 15% every year. What will the population be after 1 year?
14. 14.What amount will ₹24000 grow to in 3 years at 25% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
18. 18.What amount will ₹7800 grow to in 1 year at 8% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹29500 at 20% per year for 3 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
23. 23.What amount will ₹4500 grow to in 3 years at 20% per year compound interest (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹53500 at 20% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹40500 at 15% per year for 1 year, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹57800 at 20% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹10000 at 20% per year for 3 years, compounded every year (in ₹).
28. 28.A scooter is worth ₹26600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
29. 29.Find the compound interest on ₹11700 at 15% per year for 1 year, compounded every year (in ₹).
30. 30.What amount will ₹34500 grow to in 3 years at 20% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹41000 at 10% per year for 3 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹18000 at 5% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹22500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
36. 36.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
37. 37.A town has 49400 people. The population grows by 15% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹20400 at 5% per year for 2 years, compounded every year (in ₹).
39. 39.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
40. 40.What amount will ₹23000 grow to in 1 year at 5% per year compound interest (in ₹)?

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