Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹22800 at 15% per year for 2 years (in ₹)?
- 2.Find the compound interest on ₹48500 at 20% per year for 3 years, compounded every year (in ₹).
- 3.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
- 4.What amount will ₹52000 grow to in 1 year at 10% per year compound interest (in ₹)?
- 5.A scooter is worth ₹21600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 6.What amount will ₹58800 grow to in 1 year at 5% per year compound interest (in ₹)?
- 7.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 8.What amount will ₹51700 grow to in 2 years at 20% per year compound interest (in ₹)?
- 9.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
- 11.A scooter is worth ₹30500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 12.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
- 14.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 15.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 16.A town has 46800 people. The population grows by 5% every year. What will the population be after 2 years?
- 17.What is the difference between the compound interest and the simple interest on ₹11000 at 10% per year for 2 years (in ₹)?
- 18.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 19.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 20.Find the compound interest on ₹18400 at 10% per year for 1 year, compounded every year (in ₹).
- 21.Find the compound interest on ₹5200 at 8% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹32000 at 25% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹54400 at 5% per year for 2 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹41600 at 10% per year for 2 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹18400 at 5% per year for 2 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
- 29.What amount will ₹46400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 30.What amount will ₹2800 grow to in 1 year at 25% per year compound interest (in ₹)?
- 31.Find the compound interest on ₹7000 at 10% per year for 1 year, compounded every year (in ₹).
- 32.What amount will ₹7000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
- 34.A scooter is worth ₹43000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 35.Find the compound interest on ₹30300 at 10% per year for 2 years, compounded every year (in ₹).
- 36.What is the difference between the compound interest and the simple interest on ₹28300 at 10% per year for 2 years (in ₹)?
- 37.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 38.A town has 42000 people. The population grows by 8% every year. What will the population be after 1 year?
- 39.A town has 9800 people. The population grows by 25% every year. What will the population be after 1 year?
- 40.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
Answer key
- 513
- 35308
- 96
- 57200
- 15606
- 61740
- 18928
- 74448
- 6859
- 2175
- 19520
- 3783
- 1908
- 46305
- 14580
- 51597
- 110
- 15680
- 55566
- 1840
- 416
- 2000
- 684
- 432
- 5576
- 8736
- 46
- 396
- 51156
- 3500
- 700
- 9317
- 288
- 22016
- 6363
- 283
- 23328
- 45360
- 12250
- 52
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