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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 333 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹40600 at 20% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
  3. 3.What amount will ₹52600 grow to in 1 year at 20% per year compound interest (in ₹)?
  4. 4.What amount will ₹56100 grow to in 2 years at 10% per year compound interest (in ₹)?
  5. 5.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  6. 6.What amount will ₹30800 grow to in 1 year at 5% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
  8. 8.A town has 15600 people. The population grows by 25% every year. What will the population be after 2 years?
  9. 9.What amount will ₹52800 grow to in 1 year at 4% per year compound interest (in ₹)?
  10. 10.What amount will ₹40800 grow to in 1 year at 12% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  12. 12.What amount will ₹58100 grow to in 1 year at 8% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹12800 at 15% per year for 2 years, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹30400 at 5% per year for 2 years, compounded every year (in ₹).
  16. 16.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  17. 17.A town has 53200 people. The population grows by 15% every year. What will the population be after 2 years?
  18. 18.Find the compound interest on ₹55800 at 10% per year for 2 years, compounded every year (in ₹).
  19. 19.A town has 50000 people. The population grows by 8% every year. What will the population be after 2 years?
  20. 20.A scooter is worth ₹13200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  21. 21.Find the compound interest on ₹12000 at 10% per year for 3 years, compounded every year (in ₹).
  22. 22.A town has 8500 people. The population grows by 12% every year. What will the population be after 1 year?
  23. 23.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹4100 at 20% per year for 2 years, compounded every year (in ₹).
  25. 25.What amount will ₹45700 grow to in 1 year at 5% per year compound interest (in ₹)?
  26. 26.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
  27. 27.Find the compound interest on ₹2400 at 10% per year for 1 year, compounded every year (in ₹).
  28. 28.A scooter is worth ₹16800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  29. 29.A town has 17000 people. The population grows by 10% every year. What will the population be after 3 years?
  30. 30.Find the compound interest on ₹8000 at 15% per year for 2 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹4000 at 10% per year for 3 years, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹19000 at 4% per year for 1 year, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹46000 at 10% per year for 2 years, compounded every year (in ₹).
  34. 34.What amount will ₹5200 grow to in 1 year at 15% per year compound interest (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
  36. 36.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  37. 37.Find the compound interest on ₹41100 at 4% per year for 1 year, compounded every year (in ₹).
  38. 38.A scooter is worth ₹36100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  39. 39.A scooter is worth ₹55000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?

Answer key

  1. 1624
  2. 9984
  3. 63120
  4. 67881
  5. 14440
  6. 32340
  7. 64
  8. 24375
  9. 54912
  10. 45696
  11. 368
  12. 62748
  13. 4128
  14. 180
  15. 3116
  16. 18522
  17. 70357
  18. 11718
  19. 58320
  20. 12540
  21. 3972
  22. 9520
  23. 1836
  24. 1804
  25. 47985
  26. 73002
  27. 240
  28. 15162
  29. 22627
  30. 2580
  31. 1324
  32. 760
  33. 9660
  34. 5980
  35. 48
  36. 9826
  37. 1644
  38. 34656
  39. 40095
  40. 176

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