Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 341 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹29600 at 15% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹3600 at 15% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹22100 at 20% per year for 1 year, compounded every year (in ₹).
4. 4.A scooter is worth ₹39600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹23300 at 10% per year for 2 years (in ₹)?
6. 6.A town has 42200 people. The population grows by 10% every year. What will the population be after 1 year?
7. 7.What is the difference between the compound interest and the simple interest on ₹53800 at 20% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹15900 at 5% per year for 1 year, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹15600 at 4% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹51800 at 20% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
13. 13.What amount will ₹46700 grow to in 1 year at 8% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹44800 at 25% per year for 3 years, compounded every year (in ₹).
15. 15.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
16. 16.A scooter is worth ₹35000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
17. 17.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹38000 at 15% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹7600 at 25% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
21. 21.What amount will ₹9200 grow to in 2 years at 10% per year compound interest (in ₹)?
22. 22.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹27500 at 10% per year for 2 years (in ₹)?
24. 24.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹15900 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
28. 28.A town has 38700 people. The population grows by 12% every year. What will the population be after 1 year?
29. 29.A scooter is worth ₹39500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
30. 30.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
31. 31.Find the compound interest on ₹45000 at 8% per year for 2 years, compounded every year (in ₹).
32. 32.A town has 51700 people. The population grows by 20% every year. What will the population be after 2 years?
33. 33.Find the compound interest on ₹18300 at 8% per year for 1 year, compounded every year (in ₹).
34. 34.Find the compound interest on ₹48800 at 4% per year for 1 year, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹6800 at 15% per year for 2 years (in ₹)?
36. 36.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
37. 37.A town has 20000 people. The population grows by 8% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹30000 at 10% per year for 3 years, compounded every year (in ₹).
39. 39.A town has 50000 people. The population grows by 8% every year. What will the population be after 2 years?
40. 40.What is the difference between the compound interest and the simple interest on ₹5800 at 20% per year for 2 years (in ₹)?

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