← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 342 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
  2. 2.A town has 33700 people. The population grows by 10% every year. What will the population be after 2 years?
  3. 3.What is the difference between the compound interest and the simple interest on ₹36000 at 15% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹17000 at 20% per year for 3 years, compounded every year (in ₹).
  6. 6.What is the difference between the compound interest and the simple interest on ₹36900 at 20% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹32600 at 20% per year for 2 years (in ₹)?
  8. 8.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹14600 at 20% per year for 1 year, compounded every year (in ₹).
  10. 10.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
  11. 11.A town has 45000 people. The population grows by 12% every year. What will the population be after 2 years?
  12. 12.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  13. 13.A town has 38800 people. The population grows by 25% every year. What will the population be after 2 years?
  14. 14.What amount will ₹42100 grow to in 1 year at 25% per year compound interest (in ₹)?
  15. 15.What amount will ₹59000 grow to in 3 years at 20% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹6400 at 4% per year for 1 year, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹43500 at 20% per year for 3 years, compounded every year (in ₹).
  18. 18.A scooter is worth ₹47500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  19. 19.A town has 5600 people. The population grows by 15% every year. What will the population be after 2 years?
  20. 20.A scooter is worth ₹47000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  21. 21.Find the compound interest on ₹10400 at 15% per year for 2 years, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹53600 at 25% per year for 2 years (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹16200 at 10% per year for 2 years (in ₹)?
  24. 24.A scooter is worth ₹10400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
  26. 26.A town has 44500 people. The population grows by 20% every year. What will the population be after 3 years?
  27. 27.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
  28. 28.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹55300 at 20% per year for 2 years (in ₹)?
  30. 30.What amount will ₹39200 grow to in 1 year at 5% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹6900 at 10% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹6200 at 12% per year for 1 year, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹3200 at 5% per year for 2 years, compounded every year (in ₹).
  34. 34.A scooter is worth ₹12500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹58400 at 10% per year for 2 years (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹9000 at 20% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹32800 at 5% per year for 2 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹5000 at 20% per year for 2 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹24500 at 20% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 85169
  2. 40777
  3. 810
  4. 36
  5. 12376
  6. 1476
  7. 1304
  8. 46305
  9. 2920
  10. 15625
  11. 56448
  12. 9261
  13. 60625
  14. 52625
  15. 101952
  16. 256
  17. 31668
  18. 36784
  19. 7406
  20. 44650
  21. 3354
  22. 3350
  23. 162
  24. 5850
  25. 36
  26. 76896
  27. 468
  28. 40768
  29. 2212
  30. 41160
  31. 69
  32. 744
  33. 328
  34. 11520
  35. 612
  36. 584
  37. 360
  38. 3362
  39. 2200
  40. 17836

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets