Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 343 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹50600 at 20% per year for 1 year, compounded every year (in ₹).
2. 2.A town has 55000 people. The population grows by 8% every year. What will the population be after 2 years?
3. 3.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
4. 4.A town has 5500 people. The population grows by 20% every year. What will the population be after 1 year?
5. 5.Find the compound interest on ₹35800 at 10% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
8. 8.What amount will ₹40200 grow to in 1 year at 20% per year compound interest (in ₹)?
9. 9.What amount will ₹6400 grow to in 2 years at 15% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹19200 at 15% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
12. 12.What amount will ₹40800 grow to in 2 years at 20% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
14. 14.What amount will ₹11000 grow to in 2 years at 10% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹2400 at 20% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹47200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹29200 at 25% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹45800 at 20% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹20800 at 25% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
22. 22.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
23. 23.What amount will ₹6300 grow to in 1 year at 25% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹47600 at 5% per year for 2 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹13200 at 5% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹35200 at 20% per year for 2 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
30. 30.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
31. 31.A scooter is worth ₹45700. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
32. 32.What amount will ₹29400 grow to in 1 year at 4% per year compound interest (in ₹)?
33. 33.A town has 30500 people. The population grows by 20% every year. What will the population be after 3 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹55200 at 15% per year for 1 year, compounded every year (in ₹).
36. 36.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
37. 37.Find the compound interest on ₹20000 at 4% per year for 1 year, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
39. 39.A town has 57200 people. The population grows by 25% every year. What will the population be after 2 years?
40. 40.What amount will ₹22400 grow to in 2 years at 5% per year compound interest (in ₹)?

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