Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹16000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 2.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
- 3.What amount will ₹3200 grow to in 1 year at 4% per year compound interest (in ₹)?
- 4.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 5.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹57600 at 25% per year for 3 years, compounded every year (in ₹).
- 7.Find the compound interest on ₹9100 at 4% per year for 1 year, compounded every year (in ₹).
- 8.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
- 9.A town has 41900 people. The population grows by 5% every year. What will the population be after 1 year?
- 10.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹12000 at 5% per year for 2 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹47700 at 4% per year for 1 year, compounded every year (in ₹).
- 13.A town has 23500 people. The population grows by 20% every year. What will the population be after 3 years?
- 14.Find the compound interest on ₹16800 at 25% per year for 2 years, compounded every year (in ₹).
- 15.Find the compound interest on ₹43600 at 25% per year for 2 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹44800 at 25% per year for 3 years, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹16800 at 15% per year for 2 years (in ₹)?
- 18.A town has 23400 people. The population grows by 5% every year. What will the population be after 1 year?
- 19.A scooter is worth ₹35500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 20.What amount will ₹17500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 21.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹10800 at 25% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹26600 at 15% per year for 1 year, compounded every year (in ₹).
- 24.What amount will ₹49000 grow to in 2 years at 20% per year compound interest (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹25600 at 15% per year for 2 years (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹47900 at 20% per year for 2 years (in ₹)?
- 27.A town has 18300 people. The population grows by 10% every year. What will the population be after 2 years?
- 28.Find the compound interest on ₹15500 at 4% per year for 1 year, compounded every year (in ₹).
- 29.Find the compound interest on ₹25700 at 15% per year for 1 year, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 31.A town has 30000 people. The population grows by 4% every year. What will the population be after 2 years?
- 32.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
- 33.Find the compound interest on ₹6400 at 5% per year for 2 years, compounded every year (in ₹).
- 34.What amount will ₹26400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 35.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
- 36.A town has 13700 people. The population grows by 15% every year. What will the population be after 1 year?
- 37.What amount will ₹33700 grow to in 2 years at 20% per year compound interest (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹5600 at 10% per year for 2 years (in ₹)?
- 39.A scooter is worth ₹51000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 40.Find the compound interest on ₹39000 at 10% per year for 1 year, compounded every year (in ₹).
Answer key
- 6750
- 35075
- 3328
- 29744
- 27783
- 54900
- 364
- 10812
- 43995
- 3264
- 1230
- 1908
- 40608
- 9450
- 24525
- 42700
- 378
- 24570
- 18176
- 30240
- 16219
- 675
- 3990
- 70560
- 576
- 1916
- 22143
- 620
- 3855
- 8
- 32448
- 27450
- 656
- 34914
- 9261
- 15755
- 48528
- 56
- 46920
- 3900
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