Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹14500 at 20% per year for 2 years (in ₹)?
- 3.A town has 2000 people. The population grows by 10% every year. What will the population be after 3 years?
- 4.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 5.A town has 25200 people. The population grows by 15% every year. What will the population be after 2 years?
- 6.What amount will ₹6500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 7.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 8.A town has 46400 people. The population grows by 5% every year. What will the population be after 2 years?
- 9.What amount will ₹25400 grow to in 2 years at 10% per year compound interest (in ₹)?
- 10.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 11.A town has 52500 people. The population grows by 8% every year. What will the population be after 2 years?
- 12.A town has 16000 people. The population grows by 10% every year. What will the population be after 1 year?
- 13.A scooter is worth ₹23600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 14.What amount will ₹5700 grow to in 1 year at 5% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹22300 at 4% per year for 1 year, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹34800 at 5% per year for 2 years (in ₹)?
- 17.A town has 56200 people. The population grows by 10% every year. What will the population be after 1 year?
- 18.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
- 19.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
- 20.Find the compound interest on ₹52100 at 10% per year for 1 year, compounded every year (in ₹).
- 21.What amount will ₹46100 grow to in 1 year at 5% per year compound interest (in ₹)?
- 22.A town has 36800 people. The population grows by 25% every year. What will the population be after 3 years?
- 23.Find the compound interest on ₹57000 at 10% per year for 3 years, compounded every year (in ₹).
- 24.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 25.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
- 26.What amount will ₹5200 grow to in 2 years at 20% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹33000 at 20% per year for 3 years, compounded every year (in ₹).
- 28.What amount will ₹43900 grow to in 2 years at 20% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹34000 at 15% per year for 2 years (in ₹)?
- 30.A scooter is worth ₹33900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 31.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 32.A town has 22200 people. The population grows by 25% every year. What will the population be after 1 year?
- 33.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 34.A town has 23200 people. The population grows by 25% every year. What will the population be after 2 years?
- 35.A town has 7000 people. The population grows by 20% every year. What will the population be after 3 years?
- 36.Find the compound interest on ₹6900 at 20% per year for 2 years, compounded every year (in ₹).
- 37.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 38.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 39.A town has 29100 people. The population grows by 5% every year. What will the population be after 1 year?
- 40.A scooter is worth ₹31100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
Answer key
- 28
- 580
- 2662
- 15625
- 33327
- 11232
- 49572
- 51156
- 30734
- 6305
- 61236
- 17600
- 13275
- 5985
- 892
- 87
- 61820
- 4896
- 18750
- 5210
- 48405
- 71875
- 18867
- 18522
- 26
- 7488
- 24024
- 63216
- 765
- 31188
- 43904
- 27750
- 4913
- 36250
- 12096
- 3036
- 59488
- 21600
- 30555
- 27990
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