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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 348 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹14500 at 20% per year for 2 years (in ₹)?
  3. 3.A town has 2000 people. The population grows by 10% every year. What will the population be after 3 years?
  4. 4.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
  5. 5.A town has 25200 people. The population grows by 15% every year. What will the population be after 2 years?
  6. 6.What amount will ₹6500 grow to in 3 years at 20% per year compound interest (in ₹)?
  7. 7.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
  8. 8.A town has 46400 people. The population grows by 5% every year. What will the population be after 2 years?
  9. 9.What amount will ₹25400 grow to in 2 years at 10% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  11. 11.A town has 52500 people. The population grows by 8% every year. What will the population be after 2 years?
  12. 12.A town has 16000 people. The population grows by 10% every year. What will the population be after 1 year?
  13. 13.A scooter is worth ₹23600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  14. 14.What amount will ₹5700 grow to in 1 year at 5% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹22300 at 4% per year for 1 year, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹34800 at 5% per year for 2 years (in ₹)?
  17. 17.A town has 56200 people. The population grows by 10% every year. What will the population be after 1 year?
  18. 18.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
  19. 19.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
  20. 20.Find the compound interest on ₹52100 at 10% per year for 1 year, compounded every year (in ₹).
  21. 21.What amount will ₹46100 grow to in 1 year at 5% per year compound interest (in ₹)?
  22. 22.A town has 36800 people. The population grows by 25% every year. What will the population be after 3 years?
  23. 23.Find the compound interest on ₹57000 at 10% per year for 3 years, compounded every year (in ₹).
  24. 24.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  25. 25.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
  26. 26.What amount will ₹5200 grow to in 2 years at 20% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹33000 at 20% per year for 3 years, compounded every year (in ₹).
  28. 28.What amount will ₹43900 grow to in 2 years at 20% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹34000 at 15% per year for 2 years (in ₹)?
  30. 30.A scooter is worth ₹33900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  31. 31.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
  32. 32.A town has 22200 people. The population grows by 25% every year. What will the population be after 1 year?
  33. 33.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  34. 34.A town has 23200 people. The population grows by 25% every year. What will the population be after 2 years?
  35. 35.A town has 7000 people. The population grows by 20% every year. What will the population be after 3 years?
  36. 36.Find the compound interest on ₹6900 at 20% per year for 2 years, compounded every year (in ₹).
  37. 37.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
  38. 38.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  39. 39.A town has 29100 people. The population grows by 5% every year. What will the population be after 1 year?
  40. 40.A scooter is worth ₹31100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 28
  2. 580
  3. 2662
  4. 15625
  5. 33327
  6. 11232
  7. 49572
  8. 51156
  9. 30734
  10. 6305
  11. 61236
  12. 17600
  13. 13275
  14. 5985
  15. 892
  16. 87
  17. 61820
  18. 4896
  19. 18750
  20. 5210
  21. 48405
  22. 71875
  23. 18867
  24. 18522
  25. 26
  26. 7488
  27. 24024
  28. 63216
  29. 765
  30. 31188
  31. 43904
  32. 27750
  33. 4913
  34. 36250
  35. 12096
  36. 3036
  37. 59488
  38. 21600
  39. 30555
  40. 27990

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