Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 2.A town has 20300 people. The population grows by 25% every year. What will the population be after 1 year?
- 3.What is the difference between the compound interest and the simple interest on ₹14700 at 10% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹21200 at 5% per year for 2 years, compounded every year (in ₹).
- 5.Find the compound interest on ₹18000 at 10% per year for 3 years, compounded every year (in ₹).
- 6.Find the compound interest on ₹16600 at 20% per year for 2 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹21200 at 15% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
- 9.Find the compound interest on ₹32000 at 5% per year for 2 years, compounded every year (in ₹).
- 10.What is the difference between the compound interest and the simple interest on ₹60000 at 5% per year for 2 years (in ₹)?
- 11.What amount will ₹47000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 12.Find the compound interest on ₹38600 at 15% per year for 1 year, compounded every year (in ₹).
- 13.Find the compound interest on ₹56500 at 5% per year for 1 year, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹37400 at 10% per year for 2 years (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹26000 at 15% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹27800 at 20% per year for 1 year, compounded every year (in ₹).
- 17.Find the compound interest on ₹47500 at 12% per year for 2 years, compounded every year (in ₹).
- 18.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹52000 at 15% per year for 2 years (in ₹)?
- 20.What amount will ₹5000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 21.What amount will ₹24800 grow to in 1 year at 12% per year compound interest (in ₹)?
- 22.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 24.A scooter is worth ₹44300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 25.Find the compound interest on ₹45200 at 5% per year for 2 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
- 27.What amount will ₹20700 grow to in 1 year at 10% per year compound interest (in ₹)?
- 28.What amount will ₹26000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 29.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 30.Find the compound interest on ₹54300 at 8% per year for 1 year, compounded every year (in ₹).
- 31.What amount will ₹42500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 32.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
- 33.What amount will ₹57300 grow to in 1 year at 8% per year compound interest (in ₹)?
- 34.A scooter is worth ₹55900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 35.A town has 37500 people. The population grows by 10% every year. What will the population be after 1 year?
- 36.Find the compound interest on ₹40000 at 25% per year for 3 years, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹13200 at 15% per year for 2 years (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹56300 at 10% per year for 2 years (in ₹)?
- 39.A town has 48200 people. The population grows by 20% every year. What will the population be after 2 years?
- 40.Find the compound interest on ₹33800 at 8% per year for 1 year, compounded every year (in ₹).
Answer key
- 9261
- 25375
- 147
- 2173
- 5958
- 7304
- 477
- 78
- 3280
- 150
- 62557
- 5790
- 2825
- 374
- 585
- 5560
- 12084
- 432
- 1170
- 8640
- 27776
- 40768
- 5044
- 42085
- 4633
- 9152
- 22770
- 34606
- 32076
- 4344
- 73440
- 21350
- 61884
- 53664
- 41250
- 38125
- 297
- 563
- 69408
- 2704
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