Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 352 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹49600 at 5% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹49800 at 4% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹25200 at 25% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹49400 at 20% per year for 2 years, compounded every year (in ₹).
6. 6.A town has 44900 people. The population grows by 5% every year. What will the population be after 1 year?
7. 7.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
8. 8.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
9. 9.What amount will ₹20000 grow to in 2 years at 12% per year compound interest (in ₹)?
10. 10.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹53600 at 15% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
13. 13.A town has 55000 people. The population grows by 10% every year. What will the population be after 3 years?
14. 14.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹6400 at 5% per year for 2 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
17. 17.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).
18. 18.What amount will ₹28000 grow to in 2 years at 5% per year compound interest (in ₹)?
19. 19.A scooter is worth ₹12000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
20. 20.A town has 2500 people. The population grows by 4% every year. What will the population be after 2 years?
21. 21.What is the difference between the compound interest and the simple interest on ₹59200 at 15% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
23. 23.What amount will ₹11400 grow to in 1 year at 5% per year compound interest (in ₹)?
24. 24.What amount will ₹8000 grow to in 2 years at 5% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹46300 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.A town has 8000 people. The population grows by 15% every year. What will the population be after 2 years?
27. 27.What is the difference between the compound interest and the simple interest on ₹24000 at 5% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹47600 at 5% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹35600 at 25% per year for 2 years, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹23200 at 25% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹31800 at 10% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹53000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
34. 34.A scooter is worth ₹28000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
35. 35.Find the compound interest on ₹16400 at 15% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹11600 at 12% per year for 1 year, compounded every year (in ₹).
37. 37.A scooter is worth ₹5100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
38. 38.What amount will ₹60000 grow to in 3 years at 10% per year compound interest (in ₹)?
39. 39.A scooter is worth ₹55800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
40. 40.What amount will ₹57600 grow to in 3 years at 25% per year compound interest (in ₹)?

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