Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 355 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹12500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
2. 2.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
3. 3.What amount will ₹50300 grow to in 1 year at 8% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
6. 6.A scooter is worth ₹27500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
7. 7.A town has 33100 people. The population grows by 5% every year. What will the population be after 1 year?
8. 8.What amount will ₹49000 grow to in 3 years at 10% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹2700 at 10% per year for 1 year, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹5500 at 15% per year for 1 year, compounded every year (in ₹).
12. 12.Find the compound interest on ₹34300 at 8% per year for 1 year, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹58000 at 15% per year for 2 years (in ₹)?
14. 14.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
15. 15.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
17. 17.What amount will ₹50900 grow to in 2 years at 10% per year compound interest (in ₹)?
18. 18.What amount will ₹22400 grow to in 2 years at 25% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹17700 at 4% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹19600 grow to in 2 years at 20% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
24. 24.What amount will ₹9200 grow to in 1 year at 15% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹57600 at 5% per year for 2 years (in ₹)?
26. 26.A scooter is worth ₹38000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
27. 27.Find the compound interest on ₹30800 at 8% per year for 1 year, compounded every year (in ₹).
28. 28.Find the compound interest on ₹35000 at 10% per year for 3 years, compounded every year (in ₹).
29. 29.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
30. 30.A scooter is worth ₹3200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹4400 at 25% per year for 2 years (in ₹)?
32. 32.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹12600 at 10% per year for 2 years, compounded every year (in ₹).
34. 34.What amount will ₹35200 grow to in 2 years at 15% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹23800 at 10% per year for 1 year, compounded every year (in ₹).
36. 36.A town has 10400 people. The population grows by 25% every year. What will the population be after 2 years?
37. 37.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹6800 at 5% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹15600 at 10% per year for 1 year, compounded every year (in ₹).
40. 40.What amount will ₹50000 grow to in 2 years at 25% per year compound interest (in ₹)?

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