← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 358 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹12000 grow to in 2 years at 25% per year compound interest (in ₹)?
  2. 2.Find the compound interest on ₹32500 at 4% per year for 2 years, compounded every year (in ₹).
  3. 3.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹54100 at 10% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹47000 at 8% per year for 1 year, compounded every year (in ₹).
  7. 7.What amount will ₹47200 grow to in 1 year at 10% per year compound interest (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹19800 at 20% per year for 2 years (in ₹)?
  9. 9.A scooter is worth ₹17900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹5900 at 8% per year for 1 year, compounded every year (in ₹).
  13. 13.What amount will ₹9300 grow to in 2 years at 10% per year compound interest (in ₹)?
  14. 14.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  16. 16.A town has 12000 people. The population grows by 25% every year. What will the population be after 2 years?
  17. 17.What amount will ₹3600 grow to in 2 years at 15% per year compound interest (in ₹)?
  18. 18.A town has 11600 people. The population grows by 5% every year. What will the population be after 1 year?
  19. 19.What is the difference between the compound interest and the simple interest on ₹31600 at 5% per year for 2 years (in ₹)?
  20. 20.What amount will ₹21500 grow to in 1 year at 25% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹9500 at 20% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹35800 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹39400 at 10% per year for 2 years, compounded every year (in ₹).
  25. 25.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  26. 26.A scooter is worth ₹53100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹36000 at 5% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹47200 at 4% per year for 1 year, compounded every year (in ₹).
  29. 29.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  30. 30.A town has 4000 people. The population grows by 20% every year. What will the population be after 3 years?
  31. 31.Find the compound interest on ₹49100 at 20% per year for 1 year, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹31200 at 10% per year for 1 year, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹38500 at 10% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹28500 at 20% per year for 3 years, compounded every year (in ₹).
  35. 35.What amount will ₹58100 grow to in 1 year at 20% per year compound interest (in ₹)?
  36. 36.What amount will ₹15800 grow to in 1 year at 20% per year compound interest (in ₹)?
  37. 37.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  38. 38.Find the compound interest on ₹46800 at 20% per year for 1 year, compounded every year (in ₹).
  39. 39.A scooter is worth ₹31800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?

Answer key

  1. 18750
  2. 2652
  3. 60
  4. 56
  5. 541
  6. 3760
  7. 51920
  8. 792
  9. 16468
  10. 352
  11. 44
  12. 472
  13. 11253
  14. 32076
  15. 6305
  16. 18750
  17. 4761
  18. 12180
  19. 79
  20. 26875
  21. 380
  22. 3580
  23. 37500
  24. 8274
  25. 18522
  26. 47790
  27. 90
  28. 1888
  29. 24334
  30. 6912
  31. 9820
  32. 3120
  33. 385
  34. 20748
  35. 69720
  36. 18960
  37. 34391
  38. 9360
  39. 25440
  40. 80

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets