Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 361 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹51700 at 8% per year for 1 year, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
4. 4.What amount will ₹52300 grow to in 1 year at 8% per year compound interest (in ₹)?
5. 5.What amount will ₹28000 grow to in 3 years at 20% per year compound interest (in ₹)?
6. 6.What amount will ₹20400 grow to in 2 years at 15% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹6800 at 25% per year for 2 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹5900 at 25% per year for 1 year, compounded every year (in ₹).
9. 9.What amount will ₹16200 grow to in 1 year at 25% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹6400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
11. 11.A town has 50500 people. The population grows by 12% every year. What will the population be after 1 year?
12. 12.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹23500 at 25% per year for 1 year, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹44400 at 5% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹8100 at 10% per year for 2 years (in ₹)?
16. 16.A town has 47800 people. The population grows by 20% every year. What will the population be after 1 year?
17. 17.What amount will ₹44000 grow to in 3 years at 10% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹50000 at 10% per year for 3 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
20. 20.What amount will ₹25700 grow to in 2 years at 20% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹15000 at 8% per year for 2 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹18800 at 5% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
25. 25.What amount will ₹40000 grow to in 3 years at 25% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹9000 at 12% per year for 1 year, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹52800 at 5% per year for 2 years (in ₹)?
28. 28.A town has 43400 people. The population grows by 20% every year. What will the population be after 2 years?
29. 29.Find the compound interest on ₹21000 at 10% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹42900 at 10% per year for 1 year, compounded every year (in ₹).
31. 31.Find the compound interest on ₹30800 at 10% per year for 1 year, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹59600 at 15% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
35. 35.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
36. 36.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
37. 37.A town has 14000 people. The population grows by 8% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹14600 at 25% per year for 1 year, compounded every year (in ₹).
39. 39.What amount will ₹19000 grow to in 3 years at 10% per year compound interest (in ₹)?
40. 40.What amount will ₹48000 grow to in 3 years at 25% per year compound interest (in ₹)?

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