Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 365 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹30800 at 25% per year for 2 years (in ₹)?
3. 3.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹13100 at 4% per year for 1 year, compounded every year (in ₹).
5. 5.Find the compound interest on ₹17500 at 20% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
8. 8.A scooter is worth ₹10400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
9. 9.A town has 44400 people. The population grows by 20% every year. What will the population be after 1 year?
10. 10.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
11. 11.Find the compound interest on ₹24000 at 25% per year for 3 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹53900 at 20% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹11000 at 20% per year for 3 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹51000 at 10% per year for 3 years, compounded every year (in ₹).
15. 15.A town has 36800 people. The population grows by 25% every year. What will the population be after 2 years?
16. 16.A town has 36800 people. The population grows by 25% every year. What will the population be after 3 years?
17. 17.Find the compound interest on ₹5000 at 5% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
19. 19.Find the compound interest on ₹56200 at 20% per year for 2 years, compounded every year (in ₹).
20. 20.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹54900 at 10% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹22800 at 25% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹33200 at 12% per year for 1 year, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
26. 26.What amount will ₹56100 grow to in 2 years at 10% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹54400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
28. 28.What amount will ₹51000 grow to in 1 year at 10% per year compound interest (in ₹)?
29. 29.A town has 10400 people. The population grows by 20% every year. What will the population be after 1 year?
30. 30.What amount will ₹51700 grow to in 1 year at 12% per year compound interest (in ₹)?
31. 31.A scooter is worth ₹30600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
32. 32.What amount will ₹56700 grow to in 1 year at 25% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹16600 at 8% per year for 1 year, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹41800 at 10% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹40400 at 10% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹39900 at 20% per year for 2 years, compounded every year (in ₹).
37. 37.What amount will ₹20800 grow to in 1 year at 25% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹24100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹59600 at 15% per year for 2 years (in ₹)?

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