Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 366 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹17300 at 20% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹14500 at 15% per year for 1 year, compounded every year (in ₹).
4. 4.A scooter is worth ₹49500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
5. 5.Find the compound interest on ₹20100 at 5% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
7. 7.What amount will ₹29000 grow to in 2 years at 10% per year compound interest (in ₹)?
8. 8.What amount will ₹10800 grow to in 2 years at 5% per year compound interest (in ₹)?
9. 9.A town has 45300 people. The population grows by 5% every year. What will the population be after 1 year?
10. 10.What is the difference between the compound interest and the simple interest on ₹32600 at 20% per year for 2 years (in ₹)?
11. 11.What amount will ₹34700 grow to in 1 year at 5% per year compound interest (in ₹)?
12. 12.A scooter is worth ₹16000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
13. 13.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
14. 14.What amount will ₹39600 grow to in 2 years at 5% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
17. 17.What amount will ₹34000 grow to in 3 years at 20% per year compound interest (in ₹)?
18. 18.What amount will ₹25000 grow to in 2 years at 4% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹17100 at 20% per year for 2 years (in ₹)?
20. 20.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹53500 at 10% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
23. 23.A scooter is worth ₹53400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
24. 24.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
25. 25.A town has 2600 people. The population grows by 20% every year. What will the population be after 1 year?
26. 26.What is the difference between the compound interest and the simple interest on ₹46100 at 10% per year for 2 years (in ₹)?
27. 27.A town has 17000 people. The population grows by 5% every year. What will the population be after 1 year?
28. 28.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹3900 at 10% per year for 2 years (in ₹)?
30. 30.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
31. 31.Find the compound interest on ₹32300 at 15% per year for 1 year, compounded every year (in ₹).
32. 32.A scooter is worth ₹60000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
33. 33.A scooter is worth ₹11900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹52000 at 5% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹50000 at 10% per year for 3 years, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹21600 at 5% per year for 2 years (in ₹)?
37. 37.A scooter is worth ₹22500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹2800 at 25% per year for 2 years (in ₹)?
39. 39.A town has 26200 people. The population grows by 5% every year. What will the population be after 1 year?
40. 40.A town has 33600 people. The population grows by 25% every year. What will the population be after 3 years?

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