Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 367 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹4000 grow to in 1 year at 25% per year compound interest (in ₹)?
2. 2.A scooter is worth ₹23700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹8800 at 25% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹49600 at 15% per year for 2 years (in ₹)?
5. 5.A town has 29500 people. The population grows by 5% every year. What will the population be after 1 year?
6. 6.A scooter is worth ₹2500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
7. 7.What amount will ₹49800 grow to in 2 years at 20% per year compound interest (in ₹)?
8. 8.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
9. 9.What amount will ₹57500 grow to in 3 years at 20% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
11. 11.What amount will ₹17800 grow to in 1 year at 15% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹34100 at 10% per year for 2 years, compounded every year (in ₹).
13. 13.A town has 50000 people. The population grows by 12% every year. What will the population be after 2 years?
14. 14.What is the difference between the compound interest and the simple interest on ₹18400 at 25% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
16. 16.What amount will ₹11600 grow to in 1 year at 10% per year compound interest (in ₹)?
17. 17.What amount will ₹9000 grow to in 1 year at 5% per year compound interest (in ₹)?
18. 18.A scooter is worth ₹22400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
19. 19.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
20. 20.What amount will ₹5200 grow to in 2 years at 10% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹25900 at 20% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
23. 23.What amount will ₹46200 grow to in 1 year at 8% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹36100 at 25% per year for 1 year, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
27. 27.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹43300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
29. 29.Find the compound interest on ₹44600 at 4% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹38900 at 20% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹4400 at 15% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
33. 33.A scooter is worth ₹15500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
34. 34.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
35. 35.Find the compound interest on ₹58600 at 20% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
38. 38.A town has 2200 people. The population grows by 5% every year. What will the population be after 1 year?
39. 39.A town has 52500 people. The population grows by 12% every year. What will the population be after 2 years?
40. 40.A scooter is worth ₹60000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?

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