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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 368 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹35800 at 10% per year for 2 years, compounded every year (in ₹).
  2. 2.A town has 26700 people. The population grows by 5% every year. What will the population be after 1 year?
  3. 3.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
  4. 4.A town has 45400 people. The population grows by 10% every year. What will the population be after 1 year?
  5. 5.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹51600 at 5% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹16800 at 5% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹10300 at 5% per year for 1 year, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹25500 at 20% per year for 3 years, compounded every year (in ₹).
  10. 10.What amount will ₹47200 grow to in 2 years at 5% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹36700 at 15% per year for 1 year, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹26800 at 15% per year for 2 years, compounded every year (in ₹).
  13. 13.A scooter is worth ₹43100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  14. 14.Find the compound interest on ₹14600 at 20% per year for 1 year, compounded every year (in ₹).
  15. 15.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
  16. 16.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹22400 at 4% per year for 1 year, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹48800 at 25% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
  23. 23.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
  24. 24.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹2800 at 5% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹29800 at 25% per year for 1 year, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹6600 at 10% per year for 2 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  29. 29.A town has 33400 people. The population grows by 25% every year. What will the population be after 1 year?
  30. 30.Find the compound interest on ₹31200 at 20% per year for 2 years, compounded every year (in ₹).
  31. 31.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹47600 at 5% per year for 2 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹6800 at 25% per year for 2 years (in ₹)?
  34. 34.A scooter is worth ₹32500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹54900 at 10% per year for 2 years (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹36900 at 10% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹52800 at 12% per year for 1 year, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  39. 39.What amount will ₹26500 grow to in 1 year at 5% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹37500 at 10% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 7518
  2. 28035
  3. 88
  4. 49940
  5. 16
  6. 129
  7. 42
  8. 515
  9. 18564
  10. 52038
  11. 5505
  12. 8643
  13. 34911
  14. 2920
  15. 18816
  16. 18522
  17. 27450
  18. 80
  19. 896
  20. 3050
  21. 76
  22. 9568
  23. 68992
  24. 10923
  25. 7
  26. 7450
  27. 1386
  28. 192
  29. 41750
  30. 13728
  31. 9261
  32. 4879
  33. 425
  34. 27508
  35. 549
  36. 369
  37. 6336
  38. 504
  39. 27825
  40. 7875

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