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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 369 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹47200 grow to in 1 year at 5% per year compound interest (in ₹)?
  2. 2.A town has 55000 people. The population grows by 4% every year. What will the population be after 2 years?
  3. 3.Find the compound interest on ₹49100 at 20% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  5. 5.A scooter is worth ₹11700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  6. 6.Find the compound interest on ₹9300 at 4% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹53100 at 4% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹47600 at 25% per year for 2 years, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹53600 at 5% per year for 2 years (in ₹)?
  10. 10.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
  11. 11.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
  13. 13.What amount will ₹30000 grow to in 3 years at 10% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹18600 at 4% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹16800 at 15% per year for 2 years (in ₹)?
  16. 16.A scooter is worth ₹54200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  17. 17.What amount will ₹60000 grow to in 2 years at 5% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹6300 at 10% per year for 2 years, compounded every year (in ₹).
  19. 19.A town has 27000 people. The population grows by 10% every year. What will the population be after 3 years?
  20. 20.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹26100 at 10% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹47200 at 15% per year for 2 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹34400 at 15% per year for 2 years (in ₹)?
  24. 24.A town has 35000 people. The population grows by 10% every year. What will the population be after 3 years?
  25. 25.A scooter is worth ₹24000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  26. 26.Find the compound interest on ₹48100 at 5% per year for 1 year, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹58600 at 12% per year for 1 year, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹56000 at 25% per year for 2 years (in ₹)?
  29. 29.Find the compound interest on ₹27200 at 4% per year for 1 year, compounded every year (in ₹).
  30. 30.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹38400 at 25% per year for 3 years, compounded every year (in ₹).
  33. 33.A scooter is worth ₹8800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  34. 34.What amount will ₹32100 grow to in 1 year at 25% per year compound interest (in ₹)?
  35. 35.A town has 33600 people. The population grows by 15% every year. What will the population be after 2 years?
  36. 36.What amount will ₹11800 grow to in 1 year at 5% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  38. 38.What amount will ₹6400 grow to in 3 years at 25% per year compound interest (in ₹)?
  39. 39.A town has 46300 people. The population grows by 25% every year. What will the population be after 1 year?
  40. 40.A scooter is worth ₹15000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 49560
  2. 59488
  3. 21604
  4. 144
  5. 10764
  6. 372
  7. 2124
  8. 26775
  9. 134
  10. 48668
  11. 13356
  12. 684
  13. 39930
  14. 744
  15. 378
  16. 48780
  17. 66150
  18. 1323
  19. 35937
  20. 576
  21. 261
  22. 15222
  23. 774
  24. 46585
  25. 10125
  26. 2405
  27. 7032
  28. 3500
  29. 1088
  30. 10816
  31. 864
  32. 36600
  33. 7744
  34. 40125
  35. 44436
  36. 12390
  37. 5044
  38. 12500
  39. 57875
  40. 14400

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