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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 378 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹7700 at 15% per year for 1 year, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹11200 at 5% per year for 2 years, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹38000 at 10% per year for 3 years, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹11300 at 5% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹46000 at 10% per year for 1 year, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
  9. 9.What amount will ₹53200 grow to in 2 years at 15% per year compound interest (in ₹)?
  10. 10.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
  11. 11.A scooter is worth ₹57500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  12. 12.Find the compound interest on ₹44500 at 5% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹13200 at 15% per year for 2 years (in ₹)?
  14. 14.What amount will ₹8000 grow to in 2 years at 15% per year compound interest (in ₹)?
  15. 15.A scooter is worth ₹14800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  16. 16.A town has 43500 people. The population grows by 25% every year. What will the population be after 1 year?
  17. 17.What is the difference between the compound interest and the simple interest on ₹43700 at 10% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹7600 at 10% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹43400 at 10% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
  22. 22.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
  23. 23.Find the compound interest on ₹58100 at 10% per year for 1 year, compounded every year (in ₹).
  24. 24.What amount will ₹21600 grow to in 2 years at 25% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹21800 at 20% per year for 1 year, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹7900 at 10% per year for 2 years (in ₹)?
  27. 27.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  28. 28.What amount will ₹47700 grow to in 1 year at 15% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹32100 at 20% per year for 2 years (in ₹)?
  30. 30.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹10800 at 5% per year for 1 year, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  33. 33.A town has 12500 people. The population grows by 10% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹20400 at 10% per year for 2 years, compounded every year (in ₹).
  35. 35.What amount will ₹39400 grow to in 1 year at 4% per year compound interest (in ₹)?
  36. 36.What amount will ₹10700 grow to in 1 year at 10% per year compound interest (in ₹)?
  37. 37.What amount will ₹19600 grow to in 1 year at 8% per year compound interest (in ₹)?
  38. 38.A scooter is worth ₹24400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  39. 39.A town has 42500 people. The population grows by 4% every year. What will the population be after 2 years?
  40. 40.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?

Answer key

  1. 540
  2. 9152
  3. 1155
  4. 1148
  5. 12578
  6. 565
  7. 4600
  8. 1025
  9. 70357
  10. 49572
  11. 55200
  12. 2225
  13. 297
  14. 10580
  15. 11100
  16. 54375
  17. 437
  18. 76
  19. 434
  20. 16775
  21. 352
  22. 40768
  23. 5810
  24. 33750
  25. 4360
  26. 79
  27. 27783
  28. 54855
  29. 1284
  30. 7632
  31. 540
  32. 7566
  33. 15125
  34. 4284
  35. 40976
  36. 11770
  37. 21168
  38. 23424
  39. 45968
  40. 4

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