Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
- 2.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
- 3.Find the compound interest on ₹7700 at 15% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹11200 at 5% per year for 2 years, compounded every year (in ₹).
- 5.Find the compound interest on ₹38000 at 10% per year for 3 years, compounded every year (in ₹).
- 6.Find the compound interest on ₹11300 at 5% per year for 1 year, compounded every year (in ₹).
- 7.Find the compound interest on ₹46000 at 10% per year for 1 year, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
- 9.What amount will ₹53200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 10.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 11.A scooter is worth ₹57500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 12.Find the compound interest on ₹44500 at 5% per year for 1 year, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹13200 at 15% per year for 2 years (in ₹)?
- 14.What amount will ₹8000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 15.A scooter is worth ₹14800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 16.A town has 43500 people. The population grows by 25% every year. What will the population be after 1 year?
- 17.What is the difference between the compound interest and the simple interest on ₹43700 at 10% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹7600 at 10% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹43400 at 10% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
- 21.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
- 22.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
- 23.Find the compound interest on ₹58100 at 10% per year for 1 year, compounded every year (in ₹).
- 24.What amount will ₹21600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 25.Find the compound interest on ₹21800 at 20% per year for 1 year, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹7900 at 10% per year for 2 years (in ₹)?
- 27.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 28.What amount will ₹47700 grow to in 1 year at 15% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹32100 at 20% per year for 2 years (in ₹)?
- 30.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
- 31.Find the compound interest on ₹10800 at 5% per year for 1 year, compounded every year (in ₹).
- 32.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 33.A town has 12500 people. The population grows by 10% every year. What will the population be after 2 years?
- 34.Find the compound interest on ₹20400 at 10% per year for 2 years, compounded every year (in ₹).
- 35.What amount will ₹39400 grow to in 1 year at 4% per year compound interest (in ₹)?
- 36.What amount will ₹10700 grow to in 1 year at 10% per year compound interest (in ₹)?
- 37.What amount will ₹19600 grow to in 1 year at 8% per year compound interest (in ₹)?
- 38.A scooter is worth ₹24400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 39.A town has 42500 people. The population grows by 4% every year. What will the population be after 2 years?
- 40.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
Answer key
- 540
- 9152
- 1155
- 1148
- 12578
- 565
- 4600
- 1025
- 70357
- 49572
- 55200
- 2225
- 297
- 10580
- 11100
- 54375
- 437
- 76
- 434
- 16775
- 352
- 40768
- 5810
- 33750
- 4360
- 79
- 27783
- 54855
- 1284
- 7632
- 540
- 7566
- 15125
- 4284
- 40976
- 11770
- 21168
- 23424
- 45968
- 4
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