Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 387 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹2600 at 15% per year for 1 year, compounded every year (in ₹).
3. 3.A scooter is worth ₹7500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
4. 4.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
5. 5.A town has 33500 people. The population grows by 20% every year. What will the population be after 3 years?
6. 6.What amount will ₹28000 grow to in 1 year at 20% per year compound interest (in ₹)?
7. 7.What amount will ₹49500 grow to in 1 year at 15% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹44400 at 25% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
10. 10.A town has 24300 people. The population grows by 8% every year. What will the population be after 1 year?
11. 11.What amount will ₹4400 grow to in 2 years at 5% per year compound interest (in ₹)?
12. 12.A town has 5000 people. The population grows by 4% every year. What will the population be after 2 years?
13. 13.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹12000 at 5% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
18. 18.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹29200 at 20% per year for 2 years (in ₹)?
20. 20.What amount will ₹46400 grow to in 2 years at 25% per year compound interest (in ₹)?
21. 21.A scooter is worth ₹58000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
22. 22.Find the compound interest on ₹33900 at 5% per year for 1 year, compounded every year (in ₹).
23. 23.Find the compound interest on ₹8000 at 20% per year for 3 years, compounded every year (in ₹).
24. 24.What amount will ₹38400 grow to in 2 years at 5% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
26. 26.What amount will ₹32000 grow to in 1 year at 5% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹4400 at 15% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
29. 29.A town has 32500 people. The population grows by 5% every year. What will the population be after 1 year?
30. 30.A town has 55900 people. The population grows by 20% every year. What will the population be after 2 years?
31. 31.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹11200 at 25% per year for 2 years (in ₹)?
33. 33.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹15600 at 15% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹7400 at 12% per year for 1 year, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹10000 at 20% per year for 2 years (in ₹)?
37. 37.A town has 13600 people. The population grows by 10% every year. What will the population be after 2 years?
38. 38.What amount will ₹26700 grow to in 1 year at 8% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹14800 at 8% per year for 1 year, compounded every year (in ₹).
40. 40.What amount will ₹14800 grow to in 1 year at 20% per year compound interest (in ₹)?

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