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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 388 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹19900 at 15% per year for 1 year, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹42000 at 20% per year for 1 year, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹20800 at 15% per year for 2 years (in ₹)?
  6. 6.What amount will ₹23200 grow to in 2 years at 5% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹18800 at 12% per year for 1 year, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹39200 at 25% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹56400 at 25% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  12. 12.What amount will ₹23100 grow to in 1 year at 4% per year compound interest (in ₹)?
  13. 13.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  15. 15.A scooter is worth ₹31000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  16. 16.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹8600 at 20% per year for 2 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹7200 at 25% per year for 2 years (in ₹)?
  19. 19.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹31600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  21. 21.A town has 35700 people. The population grows by 8% every year. What will the population be after 1 year?
  22. 22.A town has 11500 people. The population grows by 10% every year. What will the population be after 1 year?
  23. 23.What is the difference between the compound interest and the simple interest on ₹16000 at 15% per year for 2 years (in ₹)?
  24. 24.A scooter is worth ₹51600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  25. 25.Find the compound interest on ₹20000 at 15% per year for 2 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹13900 at 20% per year for 2 years (in ₹)?
  27. 27.A town has 55300 people. The population grows by 10% every year. What will the population be after 2 years?
  28. 28.A scooter is worth ₹57500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  29. 29.Find the compound interest on ₹26000 at 5% per year for 2 years, compounded every year (in ₹).
  30. 30.A town has 26700 people. The population grows by 10% every year. What will the population be after 2 years?
  31. 31.What amount will ₹30000 grow to in 3 years at 10% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹59200 at 15% per year for 2 years, compounded every year (in ₹).
  33. 33.A town has 22400 people. The population grows by 25% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹4800 at 5% per year for 2 years, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
  36. 36.What amount will ₹15000 grow to in 2 years at 8% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹8200 at 4% per year for 1 year, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹56400 at 5% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹46800 at 15% per year for 2 years, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?

Answer key

  1. 2985
  2. 8400
  3. 7904
  4. 76
  5. 468
  6. 25578
  7. 192
  8. 2256
  9. 2450
  10. 3525
  11. 4
  12. 24024
  13. 24334
  14. 128
  15. 25110
  16. 3783
  17. 3784
  18. 450
  19. 5832
  20. 29072
  21. 38556
  22. 12650
  23. 360
  24. 49020
  25. 6450
  26. 556
  27. 66913
  28. 29440
  29. 2665
  30. 32307
  31. 39930
  32. 19092
  33. 35000
  34. 492
  35. 662
  36. 17496
  37. 328
  38. 141
  39. 15093
  40. 36

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