Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹5700 at 15% per year for 1 year, compounded every year (in ₹).
- 2.Find the compound interest on ₹51200 at 10% per year for 2 years, compounded every year (in ₹).
- 3.Find the compound interest on ₹53100 at 5% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹50000 at 8% per year for 2 years, compounded every year (in ₹).
- 5.A town has 15000 people. The population grows by 20% every year. What will the population be after 3 years?
- 6.What amount will ₹12000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹21200 at 25% per year for 2 years (in ₹)?
- 8.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 9.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹22400 at 5% per year for 2 years (in ₹)?
- 11.Find the compound interest on ₹43500 at 20% per year for 1 year, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹11600 at 15% per year for 2 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹28400 at 5% per year for 2 years (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹54000 at 25% per year for 2 years (in ₹)?
- 15.A town has 10600 people. The population grows by 5% every year. What will the population be after 1 year?
- 16.A scooter is worth ₹20000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹13200 at 15% per year for 2 years (in ₹)?
- 18.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 19.A town has 9800 people. The population grows by 12% every year. What will the population be after 1 year?
- 20.What amount will ₹30800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 21.A scooter is worth ₹38900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹35600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 24.Find the compound interest on ₹11400 at 20% per year for 2 years, compounded every year (in ₹).
- 25.A town has 58400 people. The population grows by 25% every year. What will the population be after 1 year?
- 26.A scooter is worth ₹38700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 27.A town has 30000 people. The population grows by 10% every year. What will the population be after 1 year?
- 28.What is the difference between the compound interest and the simple interest on ₹46800 at 15% per year for 2 years (in ₹)?
- 29.What amount will ₹49500 grow to in 1 year at 15% per year compound interest (in ₹)?
- 30.A scooter is worth ₹29900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹8800 at 5% per year for 1 year, compounded every year (in ₹).
- 33.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
- 34.A town has 32000 people. The population grows by 20% every year. What will the population be after 3 years?
- 35.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹18000 at 5% per year for 2 years, compounded every year (in ₹).
- 37.What amount will ₹55000 grow to in 1 year at 12% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹24500 at 5% per year for 1 year, compounded every year (in ₹).
- 39.A town has 17500 people. The population grows by 8% every year. What will the population be after 2 years?
- 40.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
Answer key
- 855
- 10752
- 2655
- 8320
- 25920
- 15972
- 1325
- 18432
- 64827
- 56
- 8700
- 261
- 71
- 3375
- 11130
- 16928
- 297
- 9261
- 10976
- 40733
- 29175
- 1025
- 22784
- 5016
- 73000
- 31347
- 33000
- 1053
- 56925
- 26910
- 92
- 440
- 48
- 55296
- 37044
- 1845
- 61600
- 1225
- 20412
- 4
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets