Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 392 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹40300 at 8% per year for 1 year, compounded every year (in ₹).
2. 2.A town has 32800 people. The population grows by 5% every year. What will the population be after 2 years?
3. 3.What amount will ₹11700 grow to in 2 years at 10% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹14500 at 10% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹52800 at 20% per year for 2 years (in ₹)?
7. 7.What amount will ₹49800 grow to in 1 year at 12% per year compound interest (in ₹)?
8. 8.A town has 9200 people. The population grows by 5% every year. What will the population be after 2 years?
9. 9.Find the compound interest on ₹29100 at 10% per year for 2 years, compounded every year (in ₹).
10. 10.A town has 3300 people. The population grows by 8% every year. What will the population be after 1 year?
11. 11.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹32000 at 5% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹10800 at 25% per year for 2 years, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹9600 at 25% per year for 2 years (in ₹)?
16. 16.A town has 2500 people. The population grows by 4% every year. What will the population be after 2 years?
17. 17.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹52000 at 20% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹4800 at 5% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹27000 at 20% per year for 3 years, compounded every year (in ₹).
21. 21.What amount will ₹58000 grow to in 3 years at 10% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹22000 at 15% per year for 2 years, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹40300. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
26. 26.What amount will ₹56000 grow to in 3 years at 20% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹32200 at 10% per year for 2 years, compounded every year (in ₹).
28. 28.What amount will ₹8400 grow to in 2 years at 5% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹47500 at 8% per year for 1 year, compounded every year (in ₹).
30. 30.A scooter is worth ₹6100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
31. 31.What amount will ₹55600 grow to in 1 year at 4% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹28500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
33. 33.Find the compound interest on ₹5100 at 10% per year for 1 year, compounded every year (in ₹).
34. 34.A town has 9200 people. The population grows by 20% every year. What will the population be after 2 years?
35. 35.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
36. 36.A scooter is worth ₹14400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹41500 at 20% per year for 2 years (in ₹)?
38. 38.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
39. 39.A town has 17500 people. The population grows by 12% every year. What will the population be after 2 years?
40. 40.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).

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