Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 396 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹18400 at 25% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹22800 at 4% per year for 1 year, compounded every year (in ₹).
5. 5.Find the compound interest on ₹39400 at 20% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
7. 7.A scooter is worth ₹37400. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
8. 8.Find the compound interest on ₹36400 at 15% per year for 2 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹25900 at 5% per year for 1 year, compounded every year (in ₹).
10. 10.A town has 59500 people. The population grows by 8% every year. What will the population be after 1 year?
11. 11.What amount will ₹4200 grow to in 1 year at 12% per year compound interest (in ₹)?
12. 12.A scooter is worth ₹54900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹38500 at 20% per year for 2 years (in ₹)?
14. 14.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
15. 15.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
16. 16.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
17. 17.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
18. 18.What amount will ₹7500 grow to in 1 year at 25% per year compound interest (in ₹)?
19. 19.What amount will ₹8300 grow to in 1 year at 20% per year compound interest (in ₹)?
20. 20.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
21. 21.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹34700 at 10% per year for 2 years (in ₹)?
23. 23.A town has 8500 people. The population grows by 15% every year. What will the population be after 1 year?
24. 24.What is the difference between the compound interest and the simple interest on ₹37500 at 20% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹50400 at 20% per year for 2 years (in ₹)?
26. 26.A town has 34700 people. The population grows by 4% every year. What will the population be after 1 year?
27. 27.A town has 17800 people. The population grows by 10% every year. What will the population be after 1 year?
28. 28.What amount will ₹26600 grow to in 1 year at 5% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹44700 at 20% per year for 1 year, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹23200 at 25% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹25000 at 10% per year for 2 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
33. 33.What amount will ₹15000 grow to in 2 years at 8% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹32400 at 4% per year for 1 year, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
36. 36.A scooter is worth ₹33300. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
37. 37.A scooter is worth ₹2100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
38. 38.What amount will ₹33800 grow to in 1 year at 20% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹53100 at 20% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹45000 at 4% per year for 2 years, compounded every year (in ₹).

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