Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 50200 people. The population grows by 25% every year. What will the population be after 1 year?
- 2.What is the difference between the compound interest and the simple interest on ₹24900 at 10% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹25400 at 20% per year for 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹3700 at 10% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹43600 at 25% per year for 2 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 8.A town has 32800 people. The population grows by 25% every year. What will the population be after 2 years?
- 9.A scooter is worth ₹45900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹7800 at 10% per year for 2 years (in ₹)?
- 11.A town has 17000 people. The population grows by 20% every year. What will the population be after 1 year?
- 12.Find the compound interest on ₹25500 at 15% per year for 1 year, compounded every year (in ₹).
- 13.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
- 14.What amount will ₹12800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 15.What amount will ₹35600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 17.What amount will ₹7000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
- 19.A scooter is worth ₹59600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 20.A town has 50000 people. The population grows by 10% every year. What will the population be after 3 years?
- 21.What amount will ₹27900 grow to in 1 year at 12% per year compound interest (in ₹)?
- 22.What amount will ₹2500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 23.A scooter is worth ₹51200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 24.A scooter is worth ₹32800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 25.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
- 26.A town has 33400 people. The population grows by 10% every year. What will the population be after 2 years?
- 27.Find the compound interest on ₹48800 at 10% per year for 1 year, compounded every year (in ₹).
- 28.What amount will ₹49000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
- 30.Find the compound interest on ₹43100 at 20% per year for 1 year, compounded every year (in ₹).
- 31.A town has 56000 people. The population grows by 5% every year. What will the population be after 2 years?
- 32.Find the compound interest on ₹25500 at 10% per year for 2 years, compounded every year (in ₹).
- 33.What amount will ₹59600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
- 35.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 36.A scooter is worth ₹52800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 37.A town has 15000 people. The population grows by 10% every year. What will the population be after 3 years?
- 38.Find the compound interest on ₹4300 at 15% per year for 1 year, compounded every year (in ₹).
- 39.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹50700 at 10% per year for 2 years (in ₹)?
Answer key
- 62750
- 249
- 1016
- 612
- 37
- 24525
- 48
- 51250
- 41310
- 78
- 20400
- 3825
- 15250
- 25000
- 39249
- 240
- 7350
- 304
- 43061
- 66550
- 31248
- 3136
- 36992
- 18450
- 55566
- 40414
- 4880
- 65219
- 144
- 8620
- 61740
- 5355
- 65709
- 4
- 41154
- 46464
- 19965
- 645
- 10580
- 507
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